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aksik [14]
3 years ago
5

Change the following percentages to fractions 92%, 63%​

Mathematics
1 answer:
Nikitich [7]3 years ago
3 0

Answer:

92% = 23/25        and 63% = 63/100

Step-by-step explanation:

Hope that helps!

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Suppose a fair six sided die has been relabeled so that the 6 is replaced with another 5,i.e., the sides read 1,2,3,4,5,5. If th
Anvisha [2.4K]

Answer:

P(rolling five distinct values) = 1/3888

Step-by-step explanation:

We are told that I the fair sided dice, 6 is replaced with 5.

Thus,the numbers are now;

1,2,3,4,5,5.

This means a total of 6 possible numbers appearing.

Now, in these 6 numbers there are only 5 distinct numbers since 5 occurs twice.

P(1) = 1/6

P(2) = 1/6

P(3) = 1/6

P(4) = 1/6

P(5) = 2/6

Thus,probability of rolling 5 distinct values = 1/6 × 1/6 × 1/6 × 1/6 × 2/6 = 1/3888

8 0
3 years ago
Find a value of 21 + 4(3^2 -5)
Svetllana [295]

the following answer to this question is 37.

7 0
3 years ago
): If (6x-3)(6x+3)=ax^2-b, what is the value of a? What is the value of b?
lesantik [10]
Answer: a = 36 and b = 9

Explanation:

(6x-3)(6x+3)

= 36x² - 18x - 18x - 9

= 36x² - 9



(6x-3)(6x+3) = ax² - b

36x² - 9 = ax² - b

a = 36 and b = 9

Hope it helps!
7 0
3 years ago
5x minus 6 equal 44?
Lisa [10]

Answer:

x = 10

Step-by-step explanation:

I'm not entirely sure what you're asking, however we know that:

5x-6=44

5x must be 50, as 50-6=44

50 divided by 5 is 10, so 10x

6 0
4 years ago
Read 2 more answers
A chemist examines 12 sedimentary samples for bromide concentraction. The mean bromide concentration for the sample date is 0.43
Umnica [9.8K]

Answer:

a) z = 1.645

b) Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

Step-by-step explanation:

Population is approximately normal, so we can find the normal confidence interval.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645. This is the critical value, the answer for a).

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.645*\frac{0.0325}{\sqrt{12}} = 0.015

The lower end of the interval is the sample mean subtracted by M. So it is 0.437 - 0.015 = 0.422cc/m³.

The upper end of the interval is the sample mean added to M. So it is 0.437 + 0.015 = 0.452 cc/m³.

b)

Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

4 0
3 years ago
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