$x^2+4x+8=0\qquad\text{subtract 8 from both sides}\\\\x^2+4x+8-8=0-8\\\\x^2+2(x)(2)=-8\qquad\text{add}\ 2^2\ \text{to both sides}\\\\x^2+2(x)(2)+2^2=-8+2^2\qquad\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\(x+2)^2=-8+4\\\\(x+2)^2=-4\iff x+2=\pm\sqrt{-4}\\\\x+2=\pm\sqrt{(4)(-1)}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\x+2=\pm\sqrt4\cdot\sqrt{-1}\qquad\text{use}\ \sqrt{-1}=i\\\\x+2=\pm2\cdot i\qquad\text{subtract 2 from both sides}\\\\x=-2\pm2i$

4 0

3 years ago

Solve for x. x2 - 2x - 24 = 0 -4, -6 -4, 6 2, -6 4, 6 NextReset

Katena32 [7]

-4,6
x^2 - 2x - 24 = 0
Factorise the equation
Products are -6 and 4
(x-6) (x+4) = 0
x = 6 and x = -4

Hope it helped!

4 0

3 years ago

Read 2 more answers

Three points, A, B, and C exists in space such that B is "between" A and C. It is known that AB=7, BC=4, and AC=9. Are points A,

sergeinik [125]

If the points are collinear, then that means they lie on the same line when connected to each other. In order to prove this, the distances between the points must sum up to the length of the line.

AB + BC = AC
7 + 4 ? 9
11 ≠ 9

Since they do not sum up, therefore, the points are not collinear.

7 0

3 years ago

Read 2 more answers

Which is a perfect square 61 62 63 64

leva [86]

Answer:

64 is the perfect square

Step-by-step explanation:

its the perfect square because the square root is 8 and 8 is a whole number therefore 64 is the perfect square here.

plz vote me brainliest and give me a thanks

3 0

3 years ago