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3 years ago

Please help me in this. ASAP!

Mathematics

1 answer:

Paha777 [63]3 years ago

5 0

Answer:

Thermal energy -- sand on beach feels warm to touch

Gravitational potential energy -- a piece of fruit hanging from a tree

Electric energy -- Lightning produced during a storm

Kinetic energy -- A box moving along a conveyer belt

Radiant energy -- Radio waves transmitted from a tower

Step-by-step explanation:

PLZ mark me as brainliest

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How to solve 22 – 3y > 7

nikklg [1K]

Answer:

y < 5

Step-by-step explanation:

22 – 3y > 7

=> 22 – 7 > 3y

=> 15 > 3y

=> y < 5

Therefore, y < 5 is the solution.

Hoped this helped.

3 0

3 years ago

How many 30 degree angles are in a 150 degree angle? Use repeated subtraction to solve.

sashaice [31]

150 minus 30 equals 120 but i did 150/30 and got 5

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4 years ago

What is this number in standard form?

Andrej [43]

Answer:

500.61

Step-by-step explanation:

5 multiplied by 100 = 500

1/10 = 0.1, So 6 multiplied by 0.1 = 0.6

1/100 = 0.01, So 1 multiplied by 1 = 0.01

500 + 0.6 + 0.01 = 500.61

6 0

3 years ago

Read 2 more answers

I will give brainliest if you help me

ZanzabumX [31]

Answer:

it would still be the same length due to the fact that it did not change lengths.

Step-by-step explanation:

3 0

3 years ago

Find a particular solution to y" - y + y = 2 sin(3x)

leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

$\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x$

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

$=e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}$

Multiplying both sides of equation (1) by integrating factor and integrating we get

$\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I$

$I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx$

8 0

3 years ago