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2 years ago

What is the solution of this equation 5( x - 4) = 3x + 4

Mathematics

1 answer:

Art [367]2 years ago

8 0

5 (x - 4) = 3x + 4
5x - 20 = 3x + 4
5x - 3x = 4 + 20
2x = 24
x = 12

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When calculating total gross pay, you should ___

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B( use your hourly wage and tips)

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3 years ago

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Simplify (−6.5)(−4)(−2.8)

Flura [38]

Since there are three negative numbers your product will be negative.
6.5 * 4 = 26.0
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2 years ago

Which ordered pair is a solution to this equation?

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The answer to this is (11, 1).

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3 years ago

A line passes through the points (–1, –5) and (4, 5). The point (a, 1) is also on the line.

IgorC [24]

Answer:

a = 2

Step-by-step explanation:

Let's find the equation of the line using the 2 points given.

Let's call -1 as x_1 and -5 as y_1

also, 4 as x_2 and 5 as y_2

The equation of line is :

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

<em>Let's plug the points and get the equation of the line:</em>

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\y+5=\frac{5+5}{4+1}(x+1)\\y+5=2(x+1)\\y+5=2x+2\\y=2x-3$

Now, to find a, we substitute a in x and 1 in y of the equation of the line we just got:

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4 0

3 years ago

Read 2 more answers

A dog breeder would like to know how many Dalmatian puppies are typically born in a litter. He conducts some research and select

podryga [215]

Answer:

c. 6.2 ± 2.626(0.21)

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 101 - 1 = 100

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 100 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.99}{2} = 0.995$ . So we have T = 2.626

The confidence interval is:

$\overline{x} \pm M$

In which $\overline{x}$ is the sample mean while M is the margin of error.

The distribution of the number of puppies born per litter was skewed left with a mean of 6.2 puppies born per litter.

This means that $\overline{x} = 6.2$

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2.626\frac{2.1}{\sqrt{101}} = 2.626(0.21)$

In which s is the standard deviation of the sample and n is the size of the sample.

Thus, the confidence interval is:

$\overline{x} \pm M = 6.2 \pm 2.626(0.21)$

And the correct answer is given by option c.

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3 years ago