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Oliga [24]
3 years ago
12

Y = x − 4 y=x−4 3 x + y = − 8 3x+y=−8

Mathematics
2 answers:
hjlf3 years ago
5 0

Answer:

y=−8−3x

x=−83−y3

Step-by-step explanation:

hope that helps

Lemur [1.5K]3 years ago
4 0

Answer:

what is your question?

Step-by-step explanation:

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Answer:

  First "order of operations" mistake: step 2

  First arithmetic mistake: step 4

Step-by-step explanation:

As we understand Rena's work, she wants to simplify ...

  \left(\dfrac{x^{-3}y^{-2}}{2x^4y^{-4}}\right)^{-3}

for x = -1 and y = 2.

Her work seems to be ...

<u>Step 1</u>

  \text{Substitute $x=-1$ and $y=2$ into the expression}\\\\\left(\dfrac{(-1)^{-3}2^{-2}}{2(-1)^42^{-4}}\right)^{-3}\qquad\text{no error}

<u>Step 2</u>

  \text{Simplify the parentheses}\\\\\left(\dfrac{2^4}{2(-1)^4(-1)^32^2}\right)^{-3}=\left(\dfrac{2^2}{2(-1)^7}\right)^{-3}\qquad\text{order of operations error}

<u>Step 3</u>

  \text{Evaluate the power to a power}\\\\\dfrac{2^{-6}}{2^{-3}(-1)^{21}}\qquad\text{no error}

<u>Step 4</u>

  \text{Use reciprocals and find the value}\\\\\dfrac{1}{2^32^6(-1)^{21}}=\dfrac{1}{8\cdot 64\cdot (-1)}=\dfrac{-1}{512}\qquad\text{error: $2^3$ is used instead of $2^{-3}$}

_____

So, the first arithmetic error is in Step 4. However, the order of operations requires exponents be evaluated first. Doing that makes step 2 look like ...

  \left(\dfrac{-\dfrac{1}{4}}{2(1)\dfrac{1}{16}}\right)^{-3}=(-2)^{-3}\qquad\text{proper Step 2}

__

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7 0
4 years ago
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