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2 years ago

80^2 - 45^2 = a^2 - b^2 ans pls in working, thnx in advance

Mathematics

1 answer:

Kamila [148]2 years ago

4 0

Answer:

${a}^{2} - {b}^{2}= {(80)}^{2} -{(45)}^{2} \\(a + b)(a - b) = (80 + 45)(80 - 45) \\ = 125 \times 35 = \boxed{ 4375}✓$

<h3>4375 is the right answer.</h3>

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Anika [276]

Answer:

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Step-by-step explanation:

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3 years ago

Write (b^4)^2 without exponents

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Answer:

b^8

Step-by-step explanation:

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2 years ago

34% of working mothers do not have enough money to cover their health insurance deductibles. You randomly select six working mo

tamaranim1 [39]

Answer:

solution below

Step-by-step explanation:

The question says 6 working mother's were selected so n = 6 not 0.6

We are expected to find

P(X = 0,1,2,3,4,4,6)

1. When x = 0

6C0*(0.34)⁰*(0.66)⁶

= 1 *1* 0.827

= 0.0827

2. When X = 1

6C1*(0.34)¹*(0.66)⁵

= 6 x 0.34 x 0.252

= 0.2555

3. When X = 2

6C2*(0.34)²*(0.66)⁴

= 15 x 0.1156 x 0.1897

= 0.3289

4. When x = 3

6C3*(0.34)³*(0.66)³

20 x 0.039304 x 0.2875

= 0.2599

5. When X = 4

6C4*(0.34)⁴*(0.66)²

= 15 x 0.01336 x 0.4356

= 0.8729

6. When x = 5

6C5*(0.34)⁵*(0.66)¹

= 6 x 0.0045 x 0.66

= 0.01782

7. When x = 6

6C6*(0.34)⁶*(0.66)⁰

1 x 0.0015 x 1

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3 years ago

Plz help ASAP. Need help on this

nexus9112 [7]

Answer:

RS, RT and ST

Step-by-step explanation:

A tangent to a circle is a line that meets a circle at only one point.

AP is the radius and XT is not even a line.

Hope it helps!

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3 years ago

Leicester City Fanstore (LCF) will be selling the "new season jersey" for the 2018-2019 season. The regular price of the jersey

andrew-mc [135]

Complete Question

Leicester City Fanstore (LCF) will be selling the "new season jersey" for the 2018-2019 season. The regular price of the jersey is $80. Each jersey costs $40. Leftover jerseys will be sold at the end of the season (or later) at $30. Since jerseys are produced in China and lead time is long, Puma wants LCF to decide the quantity right now (December 2017).

a. After some analysis using historic data, LCF expects that the demand will follow a Normal distribution with a mean 40,000 and a standard deviation of 8,000 due to uncertainty in team performance. How many jerseys should LCF order?

b. If a customer cannot buy the jersey from LCF (in the case of a stock-out), they may leave the store disappointed and use other channels (such as Puma stores or puma.com) in future. LCF thinks that the lost customer goodwill is around $10. Should LCF change their decision in part (a)? If yes, please state the number of jerseys LCF should order.

c. Please state whether the following statement is always true, and give a brief explanation. If $C_o =C_i$ , the news vendor solution is the mean.

Answer:

$N = 46728$

$n = 47728$

Yes it is always true

Step-by-step explanation:

From the question we are told that

The regular price of the jersey is $P_r = \$ 80$

The cost of producing a jersey is $C= \$ 40$

The left-over price of the jersey is $P_o = $ 30$

The mean is $\mu = 40000$

The standard deviation is $\sigma = 8000$

The cost of lost customer goodwill is $C_g = \$ 10$

Generally the fund that LCF will loss for one jersey if they order for too many jersey (i.e more than they need )is mathematically represented

$C_o = P_o - C$

=> $C_o = 40 - 30$

=> $C_o = \$ 10$

Generally the fund that LCF will loss for one jersey if they order lesser amount jersey (i.e less than they need )is mathematically represented

$C_i = P_r - C$

=> $C_i = 80 - 40$

=> $C_i = \$ 40$

Generally the critical ratio is mathematically represented as

$Z = \frac{C_i }{ C_i + C_o}$

=> $Z = \frac{40}{ 40 + 10}$

=> $Z = 0.8$

Generally the critical value of $Z = 0.8$ to the right of the normal curve is

$z = 0.841$

Generally the optimal quantity of jersey to order is mathematically represented as

$N = \mu * [z * \sigma]$

=> $N = 40000 * [0.841 * 8000]$

=> $N = 46728$

Considering question b

Generally considering the factor of customer goodwill the fund that LCF will loss for one jersey if they order lesser amount jersey (i.e less than they need )is mathematically represented as

$C_k = C_i + C_g$