Answer: point C = (3.75, 1.5)
Step-by-step explanation:
As the direction of the distance is from A to B, we need to down the y-axis and along (to the right) the x-axis.
Find the distance between the x-coordinates of both points by subtracting the x-coordinate of A from the x-coordinate of B:
5 - 0 = 5
3/4 of the length of this distance = 0.75 x 5 = 3.75
So the x-coordinate of C will be the sum of the distance (3.75) and the x-coordinate of A (as we are "travelling" from A to B):
3.75 + 0 = 3.75
Find the distance between the y-coordinates of both points by subtracting the y-coordinate of B from the y-coordinate of A:
3 - 1 = 2
3/4 of the length of this distance = 0.75 x 2 = 1.5
So the y-coordinate of C will be the y-coordinate of A minus the distance (1.5):
3 - 1.5 = 1.5
Therefore, point C = (3.75, 1.5)
Hope that helps - i dont know what u meant by option 1,2,3 so if u have an questions or i did it wrong i will fix it <3
The answer is 13 you subtract 25 and 12
Answer: b) they loaded 112356 lbs of cargo
Step-by-step explanation:
When a boat or an object floats in water, the volume of water that it displaces is equivalent to its weight.
When moving into the port, the cargo boat displaced 2200 ft³ of water. Since the density of water is 62.42 lb/ft³ and mass = density × volume, then the mass of the cargo boat on entering the port is
2200 × 62.42 = 137324 lbs
On leaving the port, it displaces 4000 ft³ of water. The mass of the cargo boat on leaving the port is
4000 × 62.42 = 249680 lbs
The difference in both masses is
249680 - 137324 = 112356 lbs
Therefore, they loaded 112356 lbs of cargo
It would be C.60 If you add the column of 16-20 and 21-25 it makes 60.
