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andriy [413]
3 years ago
7

The following graph shows a proportional relationship.

Mathematics
1 answer:
LenKa [72]3 years ago
4 0

Answer:

2

Step-by-step explanation:

If we look at the graph this is an increasing graph where y increases with respect to x so in other words we can say that y is directly proportional to x.

y\ \alpha\ x\\

and when we remove the proportionality sign we replace it with an equal to sign and a constant. So it becomes ,

y = kx\\

now to find the Constant of proportionality which is k we can use any ordered pair(coordinate/point) from the graph,

Lets take ( 2 , 4) where 2 represents the value of x on the x-axis and 4 represents the value of y on the y-axis so now,

y=kx\\(4)=k(2)\\4=2k\\4/2=k\\k=2\\

so the constant of proportionality is 2

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Find two positive consecutive odd integers such that the square of the large integer is one less than twice the square of the sm
andre [41]

Step-by-step explanation:

x, x+2 are the two positive consecutive of integers (x + 2, because the minimum distance between 2 odd numbers is always 2, as there can never be 2 odd numbers directly following each other; and neither can even numbers, by the way).

(x+2)² = 2×x² - 1

x² + 4x + 4 = 2x² - 1

0 = x² - 4x - 5

we can solve this by factoring.

that means we need to find a and b so that

(x - a)(x - b) = x² - 4x - 5 = 0

and x = a and x = b are the 2 solutions of the quadratic equation.

x² - ax - bx + ab = x² - 4x - 5 = 0

x² - (a+b)x + ab = x² - 4x - 5 = 0

a+b = 4

ab = -5

that means that either a or b has to be 5 and the other -1.

so, the result is

(x - 5)(x + 1) = 0

x = 5

or

x = -1

are the possible solutions.

since we are only looking for positive integers, x = -1 is not a valid solution.

and only x = 5 remains as valid solution.

therefore, the 2 positive consecutive odd integers are

5, 7

4 0
2 years ago
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2 years ago
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nika2105 [10]

Answer:

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Step-by-step explanation:

Papa maths or domes

8 0
3 years ago
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Step-by-step explanation:

7 0
3 years ago
Find the quotient of 48a^4-16a^2-32/8a^2-8
Novay_Z [31]
We know that if we had
8/6=2/2 times 4/3=1 times 4/3=4/3
find common factors in top and obttom
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48a^4-16a^2-32=(16)(a-1)(a+1)(3a^2+2)
8a^2-8=8(a-1)(a+1)
so we have
\frac{48a^4-16a^2-32}{8a^2-8} = \frac{(2)(8)(a-1)(a+1)(3a^2+2)}{(8)(a-1)(a+1)}= (\frac{8}{8}) (\frac{a-1}{a-1})( \frac{a+1}{a+1}) ( \frac{(2)(3a^{2}+2)}{1})=(2)(3a^2+2)=6a^2+4


answer is 6a^2+4
5 0
3 years ago
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