A student can take three subjects in 40 ways.
<u>SOLUTION:</u>
Given that, there are 4 different math courses, 5 different science courses, and 2 different history courses.
A student must take one of each, how many different ways can this be done?
Now, number ways to take math course = 4
Number of ways to take science course = 5
Number of ways to take history course = 2
So, now, total possible ways = product of possible ways for each course = 4 x 5 x 2 = 40 ways.
Hence, a student can take three subjects in 40 ways.
Answer:
2 times
Step-by-step explanation:
Mai biked 
miles today and Noah biked 
miles today.
We are asked how many times the length of Noah's bike ride was Mai's bike ride.
Therefore, the length of Mai's bike ride was 
times the length of Noah's bike ride.
Therefore, we will take option B will be correct. ( Answer )
Answer:
50
Step-by-step explanation:
Simple....
3x-10(x+2)=13-7x
Just solve for x.....
3x-10x-20=13-7x
-7x-20=13-7x
+7x +7x
-20=13
NO SOLUTION.
Thus, your answer.
The answer would be B. It gives you the slope and a point on the graph so use that to your advantage. All of the answers show the slope and the slope in the right place, so for now it can be any of them. Then we get to the point (10,-2). For point slope form you would switch the signs for both x and y. So the Y would now be +2 and x would be -10. Y goes together with y, and X goes together with x. In this case y+-y= slope(X+-x)
Substitute in for them. Y+2=3/5(X-10)
