I think you forgot to add a photo
SA=2H(L+W)+LW for open box
20=2H(4+W)+4(W)
distribute
20=8H+2WH+4W
divide both sides by 2
10=4H+WH+2W
solve for 1 variable, pick W
10-4H=WH+2W
10-4H=W(H+2)
(10-4H)/(H+2)=W
V=LWH
subsitute 4 for V, subsitute H for H and (10-4H)/(H+2) for W
V=(4)(H)(10-4H)/(H+2)
V=(40H-16H²)/(H+2)
find max value
take deritivitive of this thing
V'=-16(H²+4H-5)/((H+2)²)
using sign chart
sign changes from positive to negative at H=1
so at H=1
find W
W=(10-4H)/(H+2)
W=2
the dimeionts are
length=4ft
width=2ft
height=1ft
(the volume is 8 cubic feet)
200-(25•2)=150
150-(22•3)=84
84-25=59
Andrew has $59 left
Answer:
The answer to your question is the letter E. 50
Step-by-step explanation:
Data
height = ?
Width = 80 cm
Length = 40 cm
Volume = 160000 cm³
Formula
Volume of a rectangular prism = Width x length x height
Substitution
160000 = 80 x 40 x height
Solve for height
height = 160000 / 80 x 40
Simplification
height = 160000/ 3200
Result
height = 50 cm
