Answer:
P(Male or Type B) > P(Male | Type B)
Step-by-step explanation:
Total Female = 85 type A, 12 type B ⇒ 97 Female.
Total Male = 65 type A, 38 type B ⇒ 103 Male
Total type A = 65 + 85 = 150
Total type B = 12 + 38 = 50
total number of people = 97 + 103 = 200
Then the probability would be:
P(Male | Type B) = 
= 
= 0.368
P(Male or Type B) = 
= 
= 
= 
= 0.575
Hence, P(Male or Type B) > P(Male | Type B)
namely, let's rationalize the denominator in the fraction, for which case we'll be using the <u>conjugate</u> of that denominator, so we'll multiply top and bottom by its <u>conjugate</u>.
so the denominator is 5 + i, simply enough, its conjugate is just 5 - i, recall that same/same = 1, thus (5-i)/(5-i) = 1, and any expression multiplied by 1 is just itself, so we're not really changing the fraction per se.
Answer i think would be
l-4x+4l
---------
x-1
It would be d , because the lowest number which is your (min) is 72 the highest number which is your (max) is 93 . Your median would be 85 because you would add 84 & 86 and in result you would get 170 then you would divide by 2 and get 85 . Your Q1 would be 76 and your Q3 would be 91 , there is 10 numbers in total separate them (72,74,76,83,84) and (86,89,91,92,93) then find the middle number in each
Hope this helps !
<span> Honor roll Not on honor roll Total
Received math class requested 315 64 379
Did not get math class requested 41 80 121
Total 356 144 500
Honor roll: request granted: 315/356 = 0.88 x 100% = 88%
Not Honor roll request granted: 64/144 = 0.44 x 100% = 44%
Honor roll students were given preference in granting request than those not in the honor roll.</span>
