All categories

2 years ago

3p + 10 = 2p + 21 a. 15b. 17c. 11d. 21

Mathematics

2 answers:

jekas [21]2 years ago

8 0

Answer:

c. 11

Step-by-step explanation:

3p + 10 = 2p + 21

Subtract 2p from both sides.

3p - 2p + 10 = 2p - 2p + 21

Simplify.

p + 10 = 21

Subtract 10 from both sides.

p + 10 - 10 = 21 - 10

Simplify.

p = 11

Answer: c. 11

Pavel [41]2 years ago

7 0

Answer:

c.11

Step-by-step explanation:

3+10=2+21

3+10−10=2+21−10

3=2+11

3−2=2+11−2p

=11

hope this helps

have a nice day

You might be interested in

State whether the surface of the water in an aquarium is best modeled by a point, a line, a ray, or a plane.

77julia77 [94]

A line would be best used to model the surface of an aquarium, by putting a line on top of the surface and checking if the water is level or not.

7 0

3 years ago

Cheri walked 12 blocks in 36 minutes. What was Cheri's speed per minute?

Vesnalui [34]

3 is the speed per minute!

3 0

3 years ago

Read 2 more answers

5, -15, 45, -135 identify the common ratio , then write the sequence as a geometric series

Novay_Z [31]

Answer:

Common ratio: -3

Geometric sequence: an=5(-3)^n-1

Step-by-step explanation:

Each number multiplied by -3 gets the product of the next number. (5*-3= -15)

8 0

2 years ago

A car park is full. 1/3 of the cars leave.60% of the cars are red. There are 174 red cars. How many cars are left in the car par

juin [17]

Answer:

290

Step-by-step explanation:

60% of ⅔X = 174

60/100 × 2/3 × X = 174

⅖X = 174

X = 435

⅔X = ⅔×435

290

290 cars are left in the parking,

145 cars left

5 0

3 years ago

Read 2 more answers

You have D dollars to buy fence to enclose a rectangular plot of land (see figure at right). The fence for the top and bottom co

alex41 [277]

The perimeter of the rectangular plot of land is given by the expression below

$P=2x+2y$

On the other hand, since the available money to buy fence is D dollars,

$\begin{gathered} D=4(2x)+3(2y) \\ \Rightarrow D=8x+6y \\ D\rightarrow\text{ constant} \end{gathered}$

Furthermore, the area of the enclosed land is given by

$A=xy$

Solving the second equation for x,

$\begin{gathered} D=8x+6y \\ \Rightarrow x=\frac{D-6y}{8} \end{gathered}$

Substituting into the equation for the area,

$\begin{gathered} A=(\frac{D-6y}{8})y \\ \Rightarrow A=\frac{D}{8}y-\frac{3}{4}y^2 \end{gathered}$

To find the maximum possible area, solve A'(y)=0, as shown below

$\begin{gathered} A^{\prime}(y)=0 \\ \Rightarrow\frac{D}{8}-\frac{3}{2}y=0 \\ \Rightarrow\frac{3}{2}y=\frac{D}{8} \\ \Rightarrow y=\frac{D}{12} \end{gathered}$

Therefore, the corresponding value of x is

$\begin{gathered} y=\frac{D}{12} \\ \Rightarrow x=\frac{D-6(\frac{D}{12})}{8}=\frac{D-\frac{D}{2}}{8}=\frac{D}{16} \end{gathered}$ <h2>Thus, the dimensions of the fence that maximize the area are x=D/16 and y=D/12.</h2><h2>As for the used money,</h2> $\begin{gathered} top,bottom:\frac{8D}{16}=\frac{D}{2} \\ Sides:\frac{6D}{12}=\frac{D}{2} \end{gathered}$ <h2>Half the money was used for the top and the bottom, while the other half was used for the sides.</h2>

7 0

7 months ago

3p + 10 = 2p + 21 a. 15b. 17c. 11d. 21​

3p + 10 = 2p + 21 a. 15b. 17c. 11d. 21