Answer:
The maximum height of the ball is 256m
Step-by-step explanation:
Given the equation of a pathway modelled as pathway can be modeled by h = -16t² + 128t
At maximum height, the velocity of the ball is zero.
velocity = dh/dt
velocity = -32t + 128
Since v = 0 at maximum height
0 = -32t+128
32t = 128
t = 128/32
t = 4seconds
The maximum height can be gotten by substituting t = 4 into the modelled equation.
h = -16t² + 128t
h = -16(4)²+128(4)
h = -16(16)+512
h = -256+512
h = 256m
Answer:
36%
Step-by-step explanation:
the <em>complement </em>of it raining on at least one of these days = it not raining on any day
this means that if it does not rain on at least one day, it does not rain on any day
thus,
1 - probability of it not raining at all = probability it rains at least one day
probability it doesn't rain on monday = 1- 20% = 80%
probability it doesn't rain on tuesday = 1 - 20% = 80%
probability it doesn't rain on monday AND it doesn't rain on tuesday = probability it doesn't rain at all
P(A and B) = P(A) * P(B) = 0.8 * 0.8 = 0.64
1 - 0.64 = 0.36 as our answer
Slope Intercept: Y=mx + b
1. Y= -2/3x + -4
2. Y= 1/3x + 7
Answer:
6.4 minutes
Step-by-step explanation:
The question gave us the following details:
Average speed = 60mph
Time spent on trip = 8 hours
Average speed of express train on way back = 75mph
T = distance/speed
D = distance
V = speed
T = d/v
d = v(t)
d = 60 x 8
= 480
Such that
480/75
= 6.4 hours.
That is 6 hours 40 minutes is the length of time it would take on the trip home.
Thank you!
