Help do I need to measure what's on the paper or measure a real object ???

Mathematics

1 answer:

MArishka [77]3 years ago

8 0

I think its on the paper but not sure

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A chemist examines 15 geological samples for potassium chloride concentration. The mean potassium chloride concentration for the

Lelu [443]

Answer:

95% Confidence interval: (0.375,0.377)

Step-by-step explanation:

We are given the following in the question:

Sample mean, $\bar{x}$ = 0.376 cc/cubic meter

Sample size, n = 15

Alpha, α = 0.05

Sample standard deviation, s = 0.0012

Degree of freedom =

$=n-1\\=15-1\\=14$

95% Confidence interval:

$\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 14 and}~\alpha_{0.05} = \pm 2.145$

$0.376 \pm 2.145(\dfrac{0.0012}{\sqrt{15}} )\\\\ = 0.376 \pm 0.0006\\\\ = (0.3754,0.3766)\approx (0.375,0.377)$

(0.375,0.377) is the required 95% confidence interval for the population mean potassium chloride concentration.

5 0

3 years ago

Cynthia is planning a party. for entertainment, she has designed a game that involves spinning two spinners. if the sum of the n

vesna_86 [32]

The correct statement of the problem is attached

Spinner A: 4 parts, 3/4 is 1, 1/4 is 3.----------1 1 1 3
Spinner B: 3 parts, 1/3 is 5, 1/3 is 7, 1/3 is 9--------5 7 9

The combinations of the two spinners are
1 and 5
1 and 7
1 and 9
3 and 5
3 and 7
3 and 9

cases get you thrown in the pool
1 and 5
1 and 7
3 and 5

calculation of the probabilities
1 and 5--------3/4*1/3 = 1/4
1 and 7--------3/4*1/3 = 1/4
3 and 5--------1/4*1/3 = 1/12
1/4+1/4+1/12=7/12-----------58.33%

probabilities that the guests will be thrown in the pool--------58.33%