Answer:
<u>Step-by-step explanation:</u>
Insert x = 13 and y = 1:
x² + 2hxy + 12y² = 0
(13)² + 2(13)(1) + 12(1)² = 0
169 + 26h + 12 = 0
26h + 181 = 0
26h = -181
Answer:just add everything
Step-by-step explanation:
1. take the #it is being added by or wat ever and muliply it by the number you want in the sequence then subtract 1
Answer:
see below
Step-by-step explanation:
The "fundamental theorem of algebra" tells you the number of roots of a polynomial is equal to its degree. This includes real and complex roots and counts repeated roots the number of times they are repeated. (Real numbers are a subset of Complex numbers, so the choice of "complex" for this problem is appropriate.)
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The given quadratic can be solved using the quadratic formula:
for ax²+bx+c=0, the solutions are
... x = (-b±√(b²-4ac))/(2a)
Here, a=2, b=-4, c=-1, so ...
... x = (4 ±√(16 -4·2·(-1)))/(2·2)
... x = (2±√6)/2
Not sure but you can figure it out.