The triangle is an obtuse triangle. No sides are equal.
convert cm to dm
1 dm = 10 cm
side a: 20 cm ⇒ 20cm * 1dm/10cm = 20dm/10 = 2 dm
side b: 30 cm ⇒ 30cm * 1dm/10cm = 30dm/10 = 3 dm
side c: 40 cm ⇒ 40cm * 1dm/10cm = 40dm/10 = 4 dm
We need to get the area of a triangle, but first we need to solve for its height using Heron's formula
s = (a+b+c)/2 = (2+3+4)/2 = 9/2 = 4.5
<span>Area = </span>√<span>(s(s-a)(s-b)(s-c)
</span>h3/2 = √4.5(4.5-2)(4.5-3)(4.5-4)
h3/2 = √4.5(2.5)(1.5)(0.5)
h3/2 = √8.44
h3/2 = 2.91
h = (2.91*2)/3
h = 1.94
A = hb/2 = (1.94*3)/2 = 5.82/2 = 2.91 dm²
48 dm² / 2.91dm² = 16.5 or 17 tiles needed
17 x Rs200 = Rs3,400 is the total cost
Answer:
O y = (x + 5) (x + 3)
Step-by-step explanation:
y = (x + 4)² - 1
y = x² + 8x + 15
y = x² + 3x + 5x + 15
y = x(x + 3) + 5(x + 3)
y = (x + 5) (x + 3)
Answer:
the sequence is continuing by multiplying -4
Answer:
the 24×4 you have to count 4 times
Answer: Graph D will be correct graph for the given function.
Explanation:
Given function 
Since it is a bi-quadratic equation thus it must have 4 roots and (0,1) is one of its point.
Moreover, the degree of the function is even thus the end behavior of the function is
, as 
and as 
In graph A, function has four root but it does not have the end behavior same as function f(x).( because in this graph 
, as and , as .) so, it can not be the graph of given function.
In graph B, neither it has four root nor it has the end behavior same as function f(x).(because in this graph as and as .) so, it can not be the graph of given function.
In graph C, neither it has four root nor it has the same end behavior as function f(x).(because in this graph as and as
.) so, it also can not be the graph of given function.
In graph D it has four root as well as it has the same end behavior as the given function. Also it passes through the point (0,1).
Thus, graph D is the graph of given function.
