Answer:
If Naveen wants to make sure that drawing a red marble is equally likely as drawing a different color marble, then he could add ***8 red marbles to the bag***
Step-by-step explanation:
The bag that contains 6 blue marbles, 3 green marbles, and 1 red marble.
Naveen wants to make sure that drawing a red marble is equally likely as drawing a different color marble, then he could add what?
Current total number of marbles = 10
Probability of drawing a red marble = (1/10)
Probability of drawing marble of other colour = (9/10)
And we want the the probability of drawing a red marble and one of the other marble to be the same.
This means we have to add a number of red marbles.
Let the number of red marbles to be added be n.
After adding n red marbles, the probability of drawing a red marble = (n+1)/(10+n)
Probability of drawing one of the other marbles = 9/(10+n)
And the probabilities are equal
(n+1)/(10+n) = 9/(10+n)
n+1 = 9
n = 9 - 1 = 8
This makes the number of red marbles 9 and total number of marbles 18.
The probability of drawing a red marble becomes (9/18) = 0.5
Probability of drawing a marble of other colour = (9/18) = 0.5 also.
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