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jeyben [28]
3 years ago
6

Can someone help me on 2??

Mathematics
1 answer:
Minchanka [31]3 years ago
6 0

Answer:

C

Step-by-step explanation:

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How do u solve -3x=-3x
Sidana [21]

Question

how do u solve -3x=-3x

-3x - (-3x) = 0

0 = 0

True

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3 years ago
Please hurry
horrorfan [7]

Answer:

B i think

Step-by-step explanation:

4 0
3 years ago
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Which of the following expression is equivalent to 6^−7? A 1/(−6)^−7 B 1/6^7 C (−6^)−7 D 1/6^−7
german

Answer:B

Step-by-step explanation: The answer is B. 1/6^7. Your trying to find the reciprocal of 6^-7. The way you do that is put a 1 over the 6 with a power of -7 like this (6^-7)/(1) and that's how you get your answer!

8 0
3 years ago
Find the HCF of 64 and 80.
Varvara68 [4.7K]

Answer:

64=2✖️2✖️2✖️2✖️2✖️2

80=2✖️2✖️2✖️2✖️2✖️5

Common factors=2✖️2✖️2✖️2

As HCF= Product of common factors

HCF =2✖️2✖️2✖️2

HCF=16

Step-by-step explanation:

I hope this will help you:)

7 0
4 years ago
Read 2 more answers
20 POINTS!!! Use the quadratic formula above to solve for h(t) = -4.9t^2 + 8t + 1 where h is the height of the ball in meters an
Elina [12.6K]

Answer:

Two solutions: -0.12 and 1.75.

Step-by-step explanation:

The quadratic formula is:

\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}. Assuming that the x² term is a, the x term is b, and the constant is c, we can plug the values into the equation.

\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {8^2 - 4\cdot-4.9\cdot1} }}{{2\cdot-4.9}}} \end{array}

\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {64 + 19.6} }}{{-9.8}}} \end{array}

\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {83.6} }}{{-9.8}}} \end{array}

\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {9.14} }}{{-9.8}}} \end{array}

\frac{-8 + 9.14}{-9.8} = -0.12

\frac{-8-9.14}{-9.8} =1.75

Hope this helped!

3 0
3 years ago
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