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3 years ago

Janet can shovel snow from her driveway in 65 minutes. Jim can do the same job

Mathematics

1 answer:

Kay [80]3 years ago

4 0

Answer:

about 23 minutes

Step-by-step explanation:

(65x35)/(65+35)= 2,275/100= 22.75 minutes (or 23 if rounded)

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If 18.9 million computers were in use in 1980 and the number is rising by 19% annually, predict the number of computers in use i

4vir4ik [10]

18.9(1+0.19)^35, 35 is the number of years
use your calculator, you should get 661.5, round to the newest whole number 662million

4 0

3 years ago

The total number of? restaurant-purchased meals that the average person will eat in a? restaurant, in a? car, or at home in a ye

zmey [24]

Answer:

The number of restaurant-purchased meals eaten in a restaurant is 75, the number eaten in a car is 33 and the number eaten at home is 55.

Step-by-step explanation:

Suppose, the number of meals eaten in a restaurant is $x$ , in a car is $y$ and at home is $z$

The total number of meals eaten in a restaurant, in a car or at home is given as 163. So, the first equation will be......

$x+y+z=163 .............................(1)$

The total number meals eaten in a car or at home exceeds the number eaten in a restaurant by 13. So, the second equation will be......

$y+z=x+13 ................................(2)$

Twenty more restaurant-purchased meals will be eaten in a restaurant than at home. So, the third equation will be......

$x= z+20..................................(3)$

First, substituting equation (2) into equation (1), we will get........

$x+(x+13)=163\\ \\ \Rightarrow 2x+13=163\\ \\ \Rightarrow 2x=163-13=150\\ \\ \Rightarrow x=\frac{150}{2}=75$

Now plugging this $x=75$ into equation (3), we will get......

$75=z+20\\ \\ \Rightarrow z=75-20= 55$

Plugging $x=75$ and $z=55$ into equation (1) .........

$75+y+55=163\\ \\ \Rightarrow y+130=163\\ \\ \Rightarrow y=163-130=33$

So, the number of restaurant-purchased meals eaten in a restaurant is 75, the number eaten in a car is 33 and the number eaten at home is 55.

8 0

3 years ago

I need help with this question please

Novay_Z [31]

I think the answer is 80 because I’m point 2 it’s is 40 and in point 3 is 60 and in point 5 is 100 so I am guessing each goes by 20 so what is between 60 and 100 if you can’t by 20s would be 80 I don’t know if I am correct tho

4 0

4 years ago

Ive tried everything and still dont understand can you help?

vredina [299]

Answer:

13.896 kg

Step-by-step explanation:

Volume of Gold Bar = Area of [Trapezium x Length of Bar]

Length of Bar = 16 cm

Area of Trapezium = 2 × Area of Triangle + Area of Rectangle

Area of Triangle = 0.5 × 5 × 3 = 7.5 cm²

2 × Area of Triangle = 2 × 7.5 = 15 cm²

Area of Rectangle = 6 × 5 = 30 cm²

Area of Trapezium = 15 + 30 = 45 cm²

Volume of Gold Bar = 45 × 16 = 720 cm³

Density of Gold = 19.3 g/cm³

Mass of Gold Bar = 720 × 19.3 = 13896 g = 13.896 kg

Mass of Gold Bar = 13.896 kg

Therefore the mass of the Gold Bar is: 13.896 kg (kilograms).

7 0

3 years ago

Read 2 more answers

Which expressions are equivalent to 3g+6(-g+(-5))

masya89 [10]

When 3g+6(-g+(-5)) is broken down, it makes -3g+-5

4 0

4 years ago