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2 years ago

State the collision theory

Mathematics

2 answers:

8_murik_8 [283]2 years ago

8 0

Answer:

Collision theory, theory used to predict the rates of chemical reactions, particularly for gases. The collision theory is based on the assumption that for a reaction to occur it is necessary for the reacting species (atoms or molecules) to come together or collide with one another.

otez555 [7]2 years ago

8 0

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What is the inverse function of y = √ x − 1 2 , x ≥ 1 2a. y=x2−14,x≥0 b. y=x2−12,x≥0 c. y=x2+12,x≥0 d. y=x2+14,x≥0

hammer [34]

The function is :

y = √(x-12), x≥12

To find the inverse function, we interchange x and y, and then make y the subject again.

So interchanging x and y we have:

x = √(y-12)

Squaring both sides gives;

x² = y-12

Now making y the subject we have,

y = x² +12

x≥0.

Therefore the inverse function is;

y = x² +12, x≥0.

Hence the correct answer is C.

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3 years ago

Which of the following is an algebraic expression that represents the phrase X increased by 20

iren2701 [21]

Answer:

The expression means that X+20

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2 years ago

Sebastian has 10 apps on his ipad. He discovers 3/4 of the apps are learning games.How many learning games are on sebatians ipad

mars1129 [50]

Answer:

Three fourth's of 10 is 7.5 if you round that up there are 8 learning games are on Sebastian's ipad

Step-by-step explanation:

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2 years ago

I am having trouble with this relative minimum of this equation.<br>

Norma-Jean [14]

Answer:

So the approximate relative minimum is (0.4,-58.5).

Step-by-step explanation:

Ok this is a calculus approach. You have to let me know if you want this done another way.

Here are some rules I'm going to use:

$(f+g)'=f'+g'$ (Sum rule)

$(cf)'=c(f)'$ (Constant multiple rule)

$(x^n)'=nx^{n-1}$ (Power rule)

$(c)'=0$ (Constant rule)

$(x)'=1$ (Slope of y=x is 1)

$y=4x^3+13x^2-12x-56$

$y'=(4x^3+13x^2-12x-56)'$

$y'=(4x^3)'+(13x^2)'-(12x)'-(56)'$

$y'=4(x^3)'+13(x^2)'-12(x)'-0$

$y'=4(3x^2)+13(2x^1)-12(1)$

$y'=12x^2+26x-12$

Now we set y' equal to 0 and solve for the critical numbers.

$12x^2+26x-12=0$

Divide both sides by 2:

$6x^2+13x-6=0$

Compaer $6x^2+13x-6=0$ to $ax^2+bx+c=0$ to determine the values for $a=6,b=13,c=-6$ .

$a=6$

$b=13$

$c=-6$

We are going to use the quadratic formula to solve for our critical numbers, x.

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-13 \pm \sqrt{13^2-4(6)(-6)}}{2(6)}$

$x=\frac{-13 \pm \sqrt{169+144}}{12}$

$x=\frac{-13 \pm \sqrt{313}}{12}$

Let's separate the choices:

$x=\frac{-13+\sqrt{313}}{12} \text{ or } \frac{-13-\sqrt{313}}{12}$

Let's approximate both of these:

$x=0.3909838 \text{ or } -2.5576505$ .

This is a cubic function with leading coefficient 4 and 4 is positive so we know the left and right behavior of the function. The left hand side goes to negative infinity while the right hand side goes to positive infinity. So the maximum is going to occur at the earlier x while the minimum will occur at the later x.

The relative maximum is at approximately -2.5576505.

So the relative minimum is at approximate 0.3909838.

We could also verify this with more calculus of course.

Let's find the second derivative.

$f(x)=4x^3+13x^2-12x-56$