Question

Please help it's due today. Also please don't help if you don't know.​

Answer 1

Answer:

D) $8g^{6} h^{4} k^{12} -h^{25}k^{15}$

Step-by-step explanation:

You have to use the laws of exponents to solve this:

Power of a Power: $(a^{m} )^{n} = a^{mn}$. In this case, $(4g^{3} h^{2} k^{4} )^{3}$, all of the numbers in the parenthesis need to be multiplied to the power of 3: $4^{3} g^{9} h^{6} k^{12}$.

Quotient of Powers: $\frac{a^{m} }{a^{n} } = a^{m-n}$. In this case, $\frac{4^{3} g^{9} h^{6} k^{12}}{8g^{3} h^{2} }$, all of the exponents need to be subtracted (but the 4³ (64) and 8 need to be divided): $8g^{6} h^{4} k^{12}$.

Use the Power of a Power again for the expression at the right: $(h^{5} k^{3} )^{5}$. You get: $h^{25} k^{15}$. Keep the subtraction/negative sign where it is.

Together, you get: $8g^{6} h^{4} k^{12} -h^{25}k^{15}$.

Hope it helps!