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tigry1 [53]
2 years ago
13

Identify the TRUE statement relating to a property of the function y = sin x

Mathematics
1 answer:
svlad2 [7]2 years ago
6 0

The true statement relating to a property of the function y =sin x is that the maximum and minimum values of the function are 1 and -1 respectively. Option B

<h3>Properties of the function</h3>

The following are the properties of the sin trigonometric ratio of the function;

  • The sine graph rises till +1 and then falls back till -1 from where it rises again.
  • The function y = sin x is an odd function
  • The domain of y = sin x is the set of all real numbers
  • The range of sine function is the closed interval [-1, 1]
  • The amplitude of the function is half its range value
  • One cycle of the function is 6. 28

From the above listed deductions, we can see that the true statement about the function y = sin x is that the range which is always known as the maximum and minimum values of the function are 1 and - 1 respectively.

Thus, the true statement relating to a property of the function y =sin x is that the maximum and minimum values of the function are 1 and -1 respectively. Option B

Learn more about the sine function here:

brainly.com/question/9565966

#SPJ1

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Answer:

x = 0.132 + \mu

is the required relation of the diameter of an orange at the 67th percentile compare with the mean diameter.        

Step-by-step explanation:

We are given the following information in the question:

Standard Deviation, σ = 0.3 inch

We are given that the distribution of  diameters is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.67.

P( X \leq x) = P( z \leq \displaystyle\frac{x - \mu}{0.3})=0.67  

Calculation the value from standard normal z table, we have,  

P( z \leq 0.440) = 0.67

\displaystyle\frac{x - \mu}{0.3} = 0.440\\x - \mu = 0.132\\ x = 0.132 + \mu

which is the required relation of the diameter of an orange at the 67th percentile compare with the mean diameter.

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I don’t get this type of problem
JulijaS [17]

Answer:

Which type of problem ...lol u have to mention this too

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