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2 years ago

Helppp pleaseeee I’ll give brainliste

Mathematics

1 answer:

a_sh-v [17]2 years ago

4 0

Answer:

F and B

Step-by-step explanation:

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Given square NOWR, what is the value of x and y?

Rina8888 [55]

Answer:

x = 4, y = 9

Step-by-step explanation:

The angles in a square are right, that is 90°

The diagonals bisect the angles , then

6x + 21 = 45 ( subtract 21 from both sides )

6x = 24 ( divide both sides by 6 )

x = 4

------------------------------------------------

The sides of a square are congruent , then

10y - 29 = 5y + 16 ( subtract 5y from both sides )

5y - 29 = 16 ( add 29 to both sides )

5y = 45 ( divide both sides by 5 )

y = 9

8 0

3 years ago

Use the equation below to find y, if m=2, x=8, and b=3.<br>y=mx+b<br>y =

fredd [130]

Answer:

Step-by-step explanation:

y=2×8+3

=16+3=19

please like and Mark as brainliest

6 0

2 years ago

Pythagorean Theorem

Nutka1998 [239]

Make a scenario with a yard

3 0

3 years ago

Mohamed decided to track the number of leaves on the tree in his backyard each year The first year there were 500 leaves Each ye

svetlana [45]

Answer:

The required recursive formula is

$f(n)= 500\times(1.4)^{n-1}\\$

Step-by-step explanation:

Mohamed decided to track the number of leaves on the tree in his backyard each year.

The first year there were 500 leaves

$Year \: 1 = 500$

Each year thereafter the number of leaves was 40% more than the year before so that means

$Year \: 2 = 500(1+0.40) = 500\times 1.4\\$

For the third year the number of leaves increase 40% than the year before so that means

$Year \: 3 = 500\times 1.4(1+0.40) = 500 \times 1.4^{2}\\$

Similarly for fourth year,

$Year \: 4 = 500\times 1.4^{2}(1+0.40) = 500\times 1.4^{3}\\$

So we can clearly see the pattern here

Let f(n) be the number of leaves on the tree in Mohameds back yard in the nth year since he started tracking it then general recursive formula is

$f(n)= 500\times(1.4)^{n-1}\\$

This is the required recursive formula to find the number of leaves for the nth year.

Bonus:

Lets find out the number of leaves in the 10th year,

$f(10)= 500\times(1.4)^{10-1}\\\\f(10)= 500\times(1.4)^{9}\\\\f(10)= 500\times20.66\\\\f(10)= 10330$

So there will be 10330 leaves in the 10th year.

3 0

3 years ago

Read 2 more answers

Parker bought a 15-year treasury bond for a face amount of $400. The 3.5% interest will be compounded quarterly. What will the f

MArishka [77]

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6 0

3 years ago