The right system of equations to describe the situation would
be on the form:
x1 = 8000 + y1*t
and
x2 = 8000 + y2*t
where x1 and x2 represents the total money of Imogene and her
friend respectively at the end of t years.
Now for the value of amount earned, y1 and y2:
y1=8000*0.08
y2=2000*√(t-2)
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Answer:
yes
The price of marked up candy is $6.00
perentage of mark up is 300%
let the marked up amount be represented as x
let 300% mark up be represented as 3x
the equatiopn for finding the price before markup
can be represented as 3x-x=$6.
2x=$6
x=$3.
Answer:
f[g(4)] = 4
Step-by-step explanation:
Given table:

f[g(4)] is a composite function.
When calculating <u>composite functions</u>, always work from inside the brackets out.
Begin with g(4): g(4) is the value of function g(x) when x = 4.
From inspection of the given table, g(4) = -6
Therefore, f[g(4)] = f(-6)
f(-6) is the value of function f(x) when x = -6.
From inspection of the given table, f(-6) = 4
Therefore, f[g(4)] = 4
h(x) = 3^x – 2 will be negative when x is less than 0
h(2) =7
g(2)=7
This is the point they are equal
g(x)> h(x) until2
g(x)>=h(x) -2<=x<=2
Choice A