Answer:
100 in²
Step-by-step explanation:
The area of the banner is equal to the area of the initial rectangle minus the area of the cutout triangle.
The rectangle has a height of 8 inches and width of 14 inches, so its area is:
A = (8 in) (14 in) = 112 in²
The triangle has a base of 8 inches and a height of 3 inches, so its area is:
A = ½ (8 in) (3 in) = 12 in²
So the area of the banner is 112 in² − 12 in² = 100 in².
Let's use the slope intercept form of a line which is:
y=mx+b where m=slope and b=y-intercept.
Mathematically m=(y2-y1)/(x2-x1) and the y-intercept is just the value of y when x is equal to zero, where the line intercepts the y axis...
First you want to find the slope by finding two clearly identifiable points on the graph...I'll pick (4,4) and (0,1), now we can calculate the slope or "m"...
m=(4-1)/(4-0)=3/4 so now we can say our line is:
y=0.75x+b, using point (4,4) we can now solve for b.
4=0.75(4)+b
4=3+b
b=1 so the line is"
y=0.75x+1
Answer:
Expected time is 15 hours for him to get to safety.
Step-by-step explanation:
We define X as the time that this miner would get to safety.
We define Y as the door he chooses initially.
P(Y= 1) = P(Y=2)=P(Y=3) = 1/3
We have E[X|Y=1] = 3
E[X|Y] = 5 hours + E[X}
E[X|Y] = 7 hours + E[X]
Then we have
E[X] = 1/3(3 + 5 + E[X] + 7 + E[X])
We cross multiply
3*E[X] = (15 + 2E[x])
3E[X] - 2E[X] = 15
E[X] = 15
So the time it would take to get him to safety is 15 hours
