(2 1/4) x (-8) FIND THE SUM OF THIS EQUATION

Mathematics

2 answers:

mr Goodwill [35]3 years ago

6 0

Answer:

the answer is 18

Step-by-step explanation:

Charra [1.4K]3 years ago

3 0

Answer: 2-8x

Step-by-step explanation:

Since it’s the sum just add like terms no need to solve it ;) hope it helps

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???????????!!!!!!!! Please

Vadim26 [7]

Hello from MrBillDoesMath!

Answer:

x = -11, y = 6

Discussion:

I don't understand the answer shown -- "Doesn't Exist" -- especially as part of the problem statement is not displayed, BUT

-6x + 3y = 84 => divide both sides by 3

-2x + y = 84/3= 28

-2x + y = 28 (A)

Multiply X = -23 + 2Y by 2 to get

2x = - 46 + 4y (B)

Adding (A) and (B) gives

(-2x + y ) + (2x) = 28 + (-46 + 4y) =>

y = 28 -46 + 4y => as -2x + 2x = 0

y = -18 + 4y =>

18 = 3y =>

y = 6

From (A) -2x + (6) = 28 or -2x = 28 -6 = 22 so x = -11

Thank you,

MrB

5 0

3 years ago

The center of a circle lies on the line y = 4x + 1 and is tangent to the x-axis at (−3,0) . What is the equation of the circle i

Hunter-Best [27]

Answer:

$(x+3)^2+(y+11)^2=121$

Step-by-step explanation:

Consider a sketch of the problem as shown in the picture, where:

Blue line is given by y = 4x + 1.
Point B is the center of the circle.
Point A is (-3, 0).

Since the center of the circle lies on the line y = 4x +1 and is tangent to the x-axis at point A, then its radius BA is perpendicular to the x-axis. To find the coordinates of point B, we must replace x = -3 into the blue line equation: y = 4x(-3) + 1 = -11.

So, we know that the center of the circle is at B=(-3, -11). And furthermore, the radius BA is of length r=11.

Since the <em>general equation of the circle</em> of radius lenght r centered at (h, k) is given by

$(x-h)^2+(y-k)^2=r^2$