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Sauron [17]
3 years ago
15

I dd the assignment and I didn't get the right answer, the correct answer was 3/4

Mathematics
1 answer:
gtnhenbr [62]3 years ago
5 0

Answer:

Step-by-step explanation:

The 2 figures are similar so corresponding sides are in the same ratio.

The factor is the value that you have to multiply a side in the first rectangle to get the corresponding side in the second rectangle.

12 ----> 9  

So:

12 * f = 9     where f is the factor

f = 9/12 = 3/4.

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Answer:

change to improper fraction

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3 years ago
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What is the value of b in the equation (y Superscript negative 9 Baseline) Superscript b Baseline = y Superscript 45?
Whitepunk [10]

Answer:

the answer is -5

Step-by-step explanation:

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3 years ago
<img src="https://tex.z-dn.net/?f=6%20%5Cdiv%20131.4" id="TexFormula1" title="6 \div 131.4" alt="6 \div 131.4" align="absmiddle"
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Answer questions 10 and 11 based on the information below.
ollegr [7]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
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How to solve for shaded area
tamaranim1 [39]

Answer:

(a)  12.96 ft²

(b)  21.5 in²

Step-by-step explanation:

(a) For the first diagram

Area of the shaded region (A) = Area of Tripezium- area of circle

A = [1/2(a+b)h]-[πr²]............... Equation 1

Where a and b are the parallel side of the tripezium respectively, h = height of the tripezium, r = radius of the circle.

From the diagram,

Given: a = 15 ft, b = 6 ft, h = 12 ft, r = h/2 = 12/2 = 6 ft.

Constant: π = 3.14

Substitute these values into equation 1

A = [12(15+6)/2]-(3.14×6²)

A = 126-113.04

A = 12.96 ft²

(b) For the second diagram,

Area of the shaded region (A') = Area of square- area of circle

A' = (L²)-(πr²)............. Equation 2

Where L = lenght of one side of the square, r = radius of the circle

From the diagram,

Given: L = 2r = (2×5) = 10 in, r = 5 in

Substitute these values into equation 2

A' = (10²)-(3.14×5²)

A' = 100-78.5

A = 21.5 in²

5 0
3 years ago
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