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2 years ago

PLEASE HELP, THIS IS A BENCHMARK. WILL GIVE BRAINLIEST!

Mathematics

2 answers:

Ksivusya [100]2 years ago

7 0

You need a picture of the shape.

Tasya [4]2 years ago

3 0

Bsmegemeisneurmeuebeuee. E 23638 6738?g-/3

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A factory uses 1/6 of a barrel of raisins in each batch of granola bars. Yesterday, the factory used 1/2 of a barrel of raisins.

balu736 [363]

1/6 = 1 batch, 2/6 = 2 batches and so on

if the factory used 1/2, the factory used 3/6 of a barrel, which equals to 3 batches.

<em>hope it helps :)</em>

8 0

2 years ago

Choose the best estimate for the mass of a raisin.

sammy [17]

Answer:

A) 0.2g

Step-by-step explanation:

${.}$

7 0

2 years ago

Read 2 more answers

What is the value of a in the equation 38+ B equals 54 would b equals nine

Igoryamba

Answer:

If you want to know what b is then it is 16

Step-by-step explanation:

38 + b = 54

54- 38 = 16

38 + 16= 54

4 0

3 years ago

The grade appeal process at a university requires that a jury be structured by selecting six individuals randomly from a pool of

romanna [79]

Answer: a) $\dfrac{3}{874}$

b) $\dfrac{30}{3059}$

c) $\dfrac{3575}{12236}$

Step-by-step explanation:

Given : Number of students : 11

Number of faculty members : 13

Total persons : $11+13=24$

Total number of ways to structure a jury of six people from a group of 24 people :-

$^{24}C_{6}=\dfrac{24!}{6!(24-6)!}=134596$

a) Number of ways of selecting a jury of all students :-

$^{11}C_{6}=\dfrac{11!}{6!(11-6)!}=462$

Then , the probability of selecting a jury of all students :-

$\dfrac{462}{134596}=\dfrac{3}{874}$

b) Number of ways of selecting a jury of all faculty :-

$^{13}C_{6}=\dfrac{13!}{6!(13-6)!}=462$

Then , the probability of selecting a jury of all students :-

$\dfrac{1716}{134596}=\dfrac{30}{3059}$

c) Number of ways of selecting a jury of two students and four faculty :-

$^{11}C_{2}\times^{13}C_{4}=\dfrac{11!}{2!(11-2)!}\times\dfrac{13!}{4!(13-4)!}=39325$

Then , the probability of selecting a jury of all students :-

$\dfrac{39325}{134596}=\dfrac{3575}{12236}$

3 0

3 years ago

The debate team is showing a video of their recent debate. The first showing begins at 3:15 p.m. The second showing starts at 4:

Ghella [55]

Given:
3:15 pm - start of first showing.
30 minutes break;
20 minutes late - 2nd showing.
4:50 - start of second showing.

4:50 - 0:20 = 4:30 should be the start of the second showing.
4:00 - 4:30 = 1/2 hour break
3:15 - 4:00 = duration of the 1st showing. 45 minutes in all.

4:50 + 0:45 = 5:35 pm end of the 2nd showing.

Yes, the 2nd showing will be over by 6:30 pm.

7 0

3 years ago