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yanalaym [24]
2 years ago
13

Graph this line using the slope and y-intercept: y=x+9 Click to select points on the graph.

Mathematics
2 answers:
just olya [345]2 years ago
8 0

Answer:

Input work is the work done on a machine as the input force acts through the input distance. This is in contrast to output work which is a force that is applied by the body or system to something else. Output work is the work done by a machine as the output force acts through the output distance.Jan 15, 2020

defon2 years ago
4 0
Points (0,9) and (-1,8)
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Find the area of each figure
prohojiy [21]

Answer:

A=120

B=20

C=20

Total area=160 cm2

This is really weird because the numbers dont look proportional to the shape but according to the data it should be correct :/

5 0
2 years ago
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(x 2 + 2x - 1)(x 2 + 2x + 5) find product
tankabanditka [31]

Answer:

x^4+4x^3+8x^2+8x-5

Step-by-step explanation:

7 0
3 years ago
39% of 50 is what number
Simora [160]
Convert percent into a decimal by moving the percent sign two places to the left.

39% => 0.39

'Of' in math means multiply.

0.39 * 50 = 19.5
5 0
3 years ago
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Write an expression for the calculation double the number 6 and then subtract 36 divided by 12
butalik [34]
6 x 6 - 36/ 12, this is the answer
\frac{6*6 - 36}{12}
3 0
3 years ago
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Suppose we are sending a digital signal which is a string of 0s and 1s of length five. (Example stringsare 00101, 11000, 10101 a
masha68 [24]

Answer:

0.7738 = 77.38% probability that an incorrect message is received.

Step-by-step explanation:

For each bit, there are only two possible outcomes. Either it is corrupted, or it is not. The probability of a bit being corrupted is independent of any other bit. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

5% probability a bit is sent incorrectly:

This means that p = 0.05

Message of length 5

This means that n = 5

What is the probability that an incorrect message is received?

This is the probability of at least one incorrect bit, which is:

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.05)^{0}.(0.95)^{5} = 0.7738

0.7738 = 77.38% probability that an incorrect message is received.

4 0
3 years ago
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