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sukhopar [10]
3 years ago
14

Which figures are polygons?​

Mathematics
2 answers:
Hoochie [10]3 years ago
8 0

Answer: A,C,D

Step-by-step explanation:

MArishka [77]3 years ago
4 0

Answer:

pretty sure it's a, c, and d

Step-by-step explanation:

polygons have straight sides, not curved. it's a 2d figure, and it is enclosed. b doesn't fit the criteria of that because of the fact that the shape is a bit curved, as the other options do fit that criteria.

You might be interested in
In how many years will RS 1200 at the rate of 15 % interest amount to RS 1740 PLS REPLY FAST I NEED YOUR HELP​
olganol [36]

Answer:

Step-by-step explanation:

1740=1200(1.15)^x

x=2.65854602561

6 0
3 years ago
What choices are equivalent to 48/64
Harrizon [31]
There are no choices so I’m going to assume this is simplification.

Answer:
3/4 —> this is the most simplified version of that fraction.

Explanation:
48/64 can be divided by multiple things to gain fractions. You could divide it by 2 repeatedly until arriving to a fraction wherein you couldn’t split anymore.
Ex.) 48/64 = 24/32 = 12/16 = 6/8 = 3/4
All of the above answers are equivalent to 48/64.
An easier way to reach the final answer of 3/4 would be to find the greatest common factor of 48/64. You can divide both by 16 and then get to 3/4.

Hope this helps!
8 0
3 years ago
Use the given graph to determine the limit, if it exists. A coordinate graph is shown with a horizontal line crossing the y axis
Lesechka [4]

Answer:

The limit of the function does not exists.

Step-by-step explanation:

From the graph it is noticed that the value of the function is 6 from all values of x which are less than 2. At x=2, the line y=6 has open circle. It means x=2 is not included.

For x<2

f(x)=6

The value of the function is -3 from all values of x which are greater than 2. At x=2, the line y=-3 has open circle. It means x=2 is not included.

For x>2

f(x)=-3

The value of y is 1 at x=2, because of he close circles on (2,1).

For x=2

f(x)=1

Therefore the graph represents a piecewise function, which is defined as

f(x)=\begin{cases}6& \text{ if } x2 \end{cases}

The limit of a function exist at a point a if the left hand limit and right hand limit are equal.

lim_{x\rightarrow a^-}f(x)=lim_{x\rightarrow a^+}f(x)

The function is broken at x=2, therefore we have to find the left and right hand limit at x=2.

lim_{x\rightarrow 2^-}f(x)=6

lim_{x\rightarrow 2^+}f(x)=-3

6\neq-3

Since the left hand limit and right hand limit are not equal therefore the limit of the function does not exists.

6 0
3 years ago
Read 2 more answers
The coordinates of the vertices of quadrilateral ABCD are A(-3,4), B(-1,3), C(-3,-1), and D(-4,2). Jorge
Veronika [31]

Answer:

im doing the same thing bro

Step-by-step explanation:

7 0
3 years ago
Please help me <br> Find f(-4)
Katyanochek1 [597]
As x < 3, you would use the equation x^{2} -5
Plus in -4 for X and you would get (-4)^{2} -5
(-4)^{2} is equal to 16.
16-5=11&#10;
f(-4)=11
5 0
3 years ago
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