Round 254 212 610 to the nearest million

Sever21 [200]

Answer:

Step-by-step explanation:

When the exponent is attached to the trig function like that, its essentially the same thing as taking the entire function to that power.

tan^2(x) = (tanx)^2

6 0

3 years ago

1. The county fair charges $1.25 per ticket for the rides. Jermaine bought 25 tickets for the rides and spent a total of $43.75

ryzh [129]

If this were to be graphed, the independent variable would be the price of the ticket for the rides. The dependent variable would be the total cost.

The fair admission is not a variable because it is a constant price for every single person who goes into the fair.

The problem asks to use y to represent the total cost and x to represent the number of ride tickets. In order to fully write out the equation, we have to figure out what the fair admission costs.

43.75 = 1.25(25) + b

*b represents the fair admission

Multiply 1.25 by 25

43.75 = 31.25 + b

Subtract 31.25 to find what b costs.

12.50 = b

The fair admission costs $12.50.

Solution: y = 1.25x + 12.50

3 0

3 years ago

Read 2 more answers

21. A nail salon had 83 customers, 48 received a pedicure and 57 received a manicure. How many customers got both a manicure and

creativ13 [48]

Answer:

gu h-onarach tha mi a ’miannachadh gum b’ urrainn dhomh do chuideachadh, ach tha feum agam air puingean airson mo cheistean fhìn duilich!

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Katena32 [7]

Answer:

(a)

$5^{-3}=\frac{1}{125}$

(b)

$-5^{-3}=-\frac{1}{125}$

(c)

$(-5^{-3})^{-1}=-125$

(d)

$(-5^{-3})^{0}=1$

Step-by-step explanation:

(a)

$5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$5^{-3}=\frac{1}{5^3}$

$5^{-3}=\frac{1}{5\times 5\times 5}$

$5^{-3}=\frac{1}{125}$ ........Answer

(b)

$-5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$-5^{-3}=-\frac{1}{5^3}$

$-5^{-3}=-\frac{1}{5\times 5\times 5}$

$-5^{-3}=-\frac{1}{125}$ ........Answer

(c)

$(-5^{-3})^{-1}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{-1}=(-5)^{-3\times -1}$

$(-5^{-3})^{-1}=(-5)^3$

$(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)$

$(-5^{-3})^{-1}=-125$ ........Answer

(d)

$(-5^{-3})^{0}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{0}=(-5)^{-3\times 0}$

$(-5^{-3})^{-1}=(-5)^0$

we can use property

$a^0=1$

$(-5^{-3})^{0}=1$ ........Answer

4 0

3 years ago

A car motercycle leaves at noon from the same location, heading in the same direction. The average speed of the car is 30mph slo

alina1380 [7]

Answer:

speed of motorcycle = 40 mph

speed of car = 50 mph

Step-by-step explanation:

Here is the complete question

A car and a motorcycle leave at noon from the same location, heading in the same direction. The average speed of the car is 30 mph slower than twice the speed of the motorcycle. In two hours, the car is 20 miles ahead of the motorcycle. Find the speed of both the car and the motorcycle, in miles per hour.

Speed = distance / time

This question would be solved using simultaneous equation

let m = average speed of the motorcycle

c = average speed of the car

c = 2m - 30 equation 1

20 =(c - m) x 2 equation 2

insert equation 1 into equation 2 and divide through by 2

10 = (2m - 30) - m

solve for m

m = 40 mph

substitute for m in equation 1

2(40) - 20 = 50 mph

8 0

3 years ago