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2 years ago

The product of 86 and the depth of the river

Mathematics

1 answer:

aniked [119]2 years ago

4 0

Answer:

Step-by-step explanation:

Are you trying to find a variable expression? the product of 86 means multiplication so 86*n or 86n. Other than that I dont understand the question.

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3a/4+2a/3-a/12<br><br>a. a/3<br>b. 4/3<br>c. (4a)/3

insens350 [35]

Answer: C

Step-by-step explanation:

$\frac{3a}{4}+\frac{2a}{3}-\frac{a}{12}$

Find the least common denominator of 4, 3, and 12.

4-3-12 | 3

4-1-4 | 4

1-1-1 |-------- 12

The first fractions needs to be multiplied by 3, and the second fraction, by 4

$(\frac{(3a)*3}{(4)*3})+(\frac{(2a)*4}{(3)*4})-\frac{a}{12}$

Solve;

$\frac{9a}{12}+\frac{8a}{12}-\frac{a}{12}$

Add the fractions with positive signs and subtract the one with negative sign.

$\frac{(9a+8a)-a}{12}$

Solve;

$\frac{17a-a}{12}=\frac{16a}{12}$

Simplify by 4;

16/4=4

12/4=3

$\frac{4a}{3}$

4 0

3 years ago

Read 2 more answers

A rescue shelter has a total of 30 occupants. The number of legs at the shelter totals 96 legs. There are spiders and frogs at t

Katarina [22]

Answer:

Hint- Spiders have 8 legs

hint- frogs have 2 legs

Step-by-step explanation:

7 0

3 years ago

Which answer is equal to 2sqrt-28?

Oksana_A [137]

2^2-28

=4-28

=-24

that is it

4 0

3 years ago

What is the length of missing side JK? Round Answer to nearest tenth please.

zvonat [6]

Given:

Triangle LJK.

LJ = 89 in, LK = 28 in and m∠L = 42°

To find:

The length of missing side JK.

Solution:

LJ = k = 89

LK = j = 28

JK = l = ?

Using law of cosine:

$l^{2}=j^{2}+k^{2}-2 jk \cdot \cos L$

Substitute the given values.

$l^{2}=28^{2}+89^{2}-2 \cdot 28 \cdot 89 \cdot \cos 42^\circ$

$l^{2}=784+7921-4984 \cdot (0.7)$

$l^{2}=784+7921-4984 \cdot (0.7431)$

$l^{2}=784+7921-3703.6$

$l^{2}=5001.4$

Taking square root on both sides.

$l=70.7$

The length of the missing side is 70.7 in.

4 0

3 years ago

Given that these simultaneous equations

Tatiana [17]

The value of k is $(3\sqrt{ 10})/2$

<h3>How to solve the simultaneous equation?</h3>

Given:

x-y=k.............(eq i)

2x²+y²-15..............(eq ii)

We would make y the subject formula in eq ii

2x²+y²-15= 0

2x² + y²= 15

y²= 15-2x²

y= $\sqrt{15-2x^2}$ ...........(eq iii)

Substitute the value of y into eq i

x-( $\sqrt{15-2x^2}$ = k

x- ( $\sqrt{15} - 2x$ = k

k= $(3\sqrt{ 10})/2$

Read more about simultaneous equations here:

brainly.com/question/16863577

#SPJ1

3 0

1 year ago