70. Bobbie wants to make 2.00 dollars using dollars with the value of half dollars and quarters. Now, how many way he can do it?
=> half dollars = 0.5
=> quarter dollars = 0.25
Possible ways:
=> 0.5 + 0.5 + 0.5 + 0.5 = 2 dollars (4 half dollars)
=> .25 + .25 + .25 +. 25 + .25 + .25 + .25 + .25 = 2 dollars (8 quarter dollars)
=> 0.5 + 0.5 + 0.25 + 0.25 + 0.25 + 0.25 = 2 dollars
=> 0.5 + 0.5 + 0.5 + 0.25 + 0.25 = 2 dollars
=> 0.5 + 0.25 + .25 + .25 + .25 + .25 + .25 = 2 dollars
Answer:
f(-3) = -12
g(-2) = -19
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Functions
- Function Notation
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
f(x) = 3x - 3
g(x) = 3x³ + 5
f(-3) is <em>x</em> = -3 for function f(x)
g(-2) is <em>x</em> = -2 for function g(x)
<u>Step 2: Evaluate</u>
f(-3)
- Substitute in <em>x</em> [Function f(x)]: f(-3) = 3(-3) - 3
- Multiply: f(-3) = -9 - 3
- Subtract: f(-3) = -12
g(-2)
- Substitute in <em>x</em> [Function g(x)]: g(-2) = 3(-2)³ + 5
- Exponents: g(-2) = 3(-8) + 5
- Multiply: g(-2) = -24 + 5
- Add: g(-2) = -19
Answer:
x=±√6i
Step-by-step explanation:
x=±√6i
Answer: n minus c would equal c c minus b would equal z
Step-by-step explanation:
The weight of the kitten will be no less than the weight of the puppy in 1.4 + 1.2x ≥ 2.8 + 0.5x week.
<h3>What is Inequality?</h3>
Statement of an order relationship—greater than, greater than or equal to, less than, or less than or equal to—between two numbers or algebraic expressions.
Given:
A puppy weighs 2.8 pounds at birth and gained about 0.5 pounds per week.
A kitten weighs 1.4 pounds at birth and gains about 1.2 pounds per week.
puppy: 2.8 + 0.5x
Kitten: 1.4 + 1.2x
As, kitten is no less than puppy.
Kitten ≥ puppy
1.4 + 1.2x ≥ 2.8 + 0.5x
hence, the weight of the kitten will be no less than the weight of the puppy in 1.4 + 1.2x ≥ 2.8 + 0.5x week.
Learn more about inequality here:
brainly.com/question/23575974
#SPJ1
