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Natali5045456 [20]
2 years ago
6

Quadrilateral A'B'C'D' is the image of quadrilateral ABCD under a rotation about the origin, (0,0). y 71 c 3+ 2+ 2 1 2 3 4 5 6 7

--7--6 -5 4 -3 -2 D' -2+ -3+ 4F B-6+ -75 Determine the angles of rotation. Choose all answers that apply: A 90° clockwise 90° counterclockwise 180° 270° clockwise 270 counterclockwise ​
Mathematics
1 answer:
VLD [36.1K]2 years ago
7 0

Answer:

give me the bubble bubble I really do not know

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The monthly utility bills in a city at e normally distributed, with a mean $100 and a standard deviation of $13. find the probab
dmitriy555 [2]

Answer:

how's your day

Step-by-step explanation:

how's your day

5 0
2 years ago
PLEASE HELP WITH NUMBER 11 ASAP!!!! (Please show how you got the answer)
Alex777 [14]

Answer:

Triangle B is right

Step-by-step explanation:

Using the converse theorem of Pythagoras.

If the square of the longest side in a triangle equals the sum of the squares of the other 2 sides then the triangle is right.

Triangle A

longest side squared = 36² = 1296

26² + 18² = 676 + 324 = 1000 ≠ 1296

Hence triangle A is not right

Triangle B

longest side squared = 25² = 625

20² + 15² = 400 + 225 = 625 ← correct

Hence triangle B is right


7 0
3 years ago
The whole is 1,000,000 50,000 is what percent of that
Travka [436]
5% is your answer bud
8 0
2 years ago
Plant A: A graph has time (weeks) on the x-axis, and height (inches) on the y-axis. A line goes through points (0, 3), (1, 4.8),
butalik [34]

Answer:

The correct option is;

No, The greater rate of change of Plant A will result in it being 0.9 inches taller in 6 weeks

Step-by-step explanation:

The parameters given are;

Plant A:

Weeks,    Height

0,               3

1,                4.8

2,               6.6

3,               8.4

The rate of change of height, H per week, t,\left (\dfrac{dH}{dt} \right )  for plant A per week is therefore;

\dfrac{dH}{dt} =  \dfrac{H_n - H_{(n-1)} }{t_n - t_{(n-1)}} = \dfrac{8.4 - 3 }{3 - 0} = \dfrac{5.4}{3} = 1.8 \ inches/week

Therefore we have;

H = 1.8 × t + 3

At week 6,

H = 3 + 6×1.8 = 13.8 inches

Plant B

Weeks,    Height

2,               7.3

3,               8.7

4,               10.1

The rate of change of height, H per week, t,\left (\dfrac{dH}{dt} \right )  for plant B per week is given as follows;

\dfrac{dH}{dt} =  \dfrac{H_n - H_{(n-1)} }{t_n - t_{(n-1)}} = \dfrac{10.1 - 7.3 }{4 - 2} = \dfrac{2.8}{2} = 1.4 \ inches/week

Therefore we have;

When t = 2, H = 7.3 hence, 7.3 = 2 × 1.4 + H₀

Where:

H₀ = H at t = 0

H₀ = 7.3 - 2 × 1.4 = 4.5

At week 6 we have;

H = 4.5 + 6×1.4 = 12.9 inches

Which indicates that Plant A will be 0.9 inches taller than Plant B at week 6.

The correct option is therefore;

No, The greater rate of change of Plant A will result in it being 0.9 inches taller in 6 weeks.

5 0
3 years ago
Read 2 more answers
I will mark brainliest 18.91 rounded to the nearest cent
siniylev [52]

Answer:

18.91

Step-by-step explanation:

18.91

The one is in the cents place, so we cannot round because there are no more digits

4 0
3 years ago
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