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Natali5045456 [20]
2 years ago
6

Quadrilateral A'B'C'D' is the image of quadrilateral ABCD under a rotation about the origin, (0,0). y 71 c 3+ 2+ 2 1 2 3 4 5 6 7

--7--6 -5 4 -3 -2 D' -2+ -3+ 4F B-6+ -75 Determine the angles of rotation. Choose all answers that apply: A 90° clockwise 90° counterclockwise 180° 270° clockwise 270 counterclockwise ​
Mathematics
1 answer:
VLD [36.1K]2 years ago
7 0

Answer:

give me the bubble bubble I really do not know

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Birds arrive at a birdfeeder according to a Poisson process at a rate of six per hour.
m_a_m_a [10]

Answer:

a) time=10 \frac{1}{6}=\frac{10}{6}=1.67 hours

b) P(T\geq 0.25h)=e^{-(6)0.25}=0.22313

c) P(T\leq 0.0833)=1-e^{-(6)0.0833}=0.39347

Step-by-step explanation:

Definitions and concepts

The Poisson process is useful when we want to analyze the probability of ocurrence of an event in a time specified. The probability distribution for a random variable X following the Poisson distribution is given by:

P(X=x) =\lambda^x \frac{e^{-\lambda}}{x!}

And the parameter \lambda represent the average ocurrence rate per unit of time.

The exponential distribution is useful when we want to describ the waiting time between Poisson occurrences. If we assume that the random variable T represent the waiting time btween two consecutive event, we can define the probability that 0 events occurs between the start and a time t, like this:

P(T>t)= e^{-\lambda t}

a. What is the expected time you would have to wait to see ten birds arrive?

The original rate for the Poisson process is given by the problem "rate of six per hour" and on this case since we want the expected waiting time for 10 birds we have this:

time=10 \frac{1}{6}=\frac{10}{6}=1.67 hours

b. What is the probability that the elapsed time between the second and third birds exceeds fifteen minutes?

Assuming that the time between the arrival of two birds consecutive follows th exponential distribution and we need that this time exceeds fifteen minutes. If we convert the 15 minutes to hours we have 15(1/60)=0.25 hours. And we want to find this probability:

P(T\geq 0.25h)

And we can use the result obtained from the definitions and we have this:

P(T\geq 0.25h)=e^{-(6)0.25}=0.22313

c. If you have already waited five minutes for the first bird to arrive, what is the probability that the bird will arrive within the next five minutes?

First we need to convert the 5 minutes to hours and we got 5(1/60)=0.0833h. And on this case we want a conditional probability. And for this case is good to remember the "Markovian property of the Exponential distribution", given by :

P(T \leq a +t |T>t)=P(T\leq a)

Since we have a waiting time for the first bird of 5 min = 0.0833h and we want that the next bird will arrive within 5 minutes=0.0833h, we can express on this way the probability of interest:

P(T\leq 0.0833+0.0833| T>0.0833)

P(T\leq 0.1667| T>0.0833)

And using the Markovian property we have this:

P(T\leq 0.0833)=1-e^{-(6)0.0833}=0.39347

3 0
3 years ago
Could some please help and explain?
Sophie [7]

Answer:

x = 7

Step-by-step explanation:

A rhombus is a parallelogram where all sides are equal. Therefore, as we know two sides are equal to 7x+8 and 9x-6, we can say that

7x+8 = 9x - 6

subtract 7x from both sides to put the variable on one side

2x - 6 = 8

add 6 to both sides to isolate the variable and its coefficient

2x = 14

divide both sides by 2 to isolate x

x = 7

7 0
2 years ago
How to solve (2.31*10^-6)+(5.87*10^-4)
S_A_V [24]

We want to calculate the following

2.31\cdot10^{-6}+5.87\cdot10^{-4}

Using the properties of exponents, we have that

10^{-6}=10^{-4}\cdot10^{-2}

So we have

2.31\cdot10^{-6}+5.87\cdot10^{-4}=2.31\cdot10^{-2}\cdot10^{-4}+5.87\cdot10^{-4}

So, if factor 10^-4 on the right side, we have

10^{-4}(2.31\cdot10^{-2}+5.87)

Note that

2.31\cdot10^{-2}=0.0231

Then,

5.87+2.31\cdot10^{-2}=5.87+0.0231=5.8931^{}

So we have that

2.31\cdot10^{-6}+5.87\cdot10^{-4}=5.8931\cdot10^{-4}

5 0
1 year ago
Can u please help me i dont get it please thank u soo much
Bumek [7]

12pm: -3° + 4° = 1°

7pm: 1° - 5° = -4°

the answer is C.

7 0
3 years ago
The area of a square patch of grass is 25 square meters .how long is each side of the patch
77julia77 [94]
The area of a square with sides of length s is

A=s^2, and we are told A=25 so

s^2=25

s=√25

s=5m
5 0
3 years ago
Read 2 more answers
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