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4 years ago

Which number produces an irrational number when multiplied by 0.4

2 answers:

3 0

Assuming 0.4 is in fact, 2 divided by 5 (and not an approximation of some number that would require an infinite amount of decimal places to exactly express), then multiplication by 0.4 is the same as multiplying by 2 and dividing by 5.

This means that multiplying any rational number by 2/5 will yield another rational number (as given x/y as an input, where x and y are integers, and multiplying it by 2/5 giving 2x/5y, will mean that 2x and 5y are also integers, and the result is also rational)

If we multiply an irrational number by 2/5, however, the result will be irrational.

So your answer is any number not in the set of rational numbers, multiplied by 0.4, will yield an irrational number.

kakasveta [241]4 years ago

3 0

Irrational number is a number without a perfect square root.

=2,3,5,6,7,8

You might be interested in

-5y-9 =-(-1)<br> A.- 1/2<br> B. -2 1/2<br> C. -2<br> D. -2/5

lbvjy [14]

Answer:

-5y=1+9

-5y=10

Y=-2

Your answer is C

3 0

3 years ago

Between what two consecutive integers is <img src="https://tex.z-dn.net/?f=%5Csqrt182" id="TexFormula1" title="\sqrt182" alt="\s

Elden [556K]

Answer:

C. 13 and 14

Step-by-step explanation:

They notice that the square root of 182 is between 13 an 14, and it gives them the idea that the numbers 13 and 14 are the solution.

Let n be the smaller of the two consecutive integers.

Then the other integer is (n+1).

We are given that

n*(n+1) = 182.

Simplify

n^2 + n - 182 = 0,

Factor left side

(n-13)*(n+14) = 0.

The solutions are n= 13 and n= -14.

You may check that both of them satisfy the problem' condition, giving you two answers

the pair (13,14) and the pair (-14,-13).

Many people prefer to solve this problem in a short way.

They notice that the square root of 182 is between 13 an 14,

and it gives them the idea that the numbers 13 and 14 are the solution.

Then these people get the next idea that if the product of 13 and 14 is equal to 182,

then the product of the opposite numbers is also 182, so

both the pairs (13,14) and (-14,-13) are solutions.

Solved and explained in detailed and short modes.

7 0

3 years ago

Translate the sentence into an inequality.

Vadim26 [7]

Answer:

9(n + 22) ≤ -15

Step-by-step explanation:

9 times the sum of a number and 22 is at most −15

Let n = number

Times = multiplication

Sum = Addition

9 * n + 22

We must add parenthesis on the end on 22 and before n

We must do this because it says 9 times the sum of a number and 22 which means that 9 is being multiplied by both n and 22

We would have 9(n + 22)

9(n + 22) is at most -15

At most meaning that -15 is the highest number that 9(n + 22) can equal

Because it says at most 9(n + 22) can equal -15 or anything less than -15

So at most can be replaced with ≤

9(n + 22) ≤ -15

4 0

3 years ago

Prove that the diagonals of a parallelogram bisect each other

Nady [450]

Answer:

[ See the attached picture ]

The diagonals of a parallelogram bisect each other.

✧ Given : ABCD is a parallelogram. Diagonals AC and BD intersect at O.

✺ To prove : AC and BD bisect each other at O , i.e AO = OC and BO = OD.

Proof : $\begin{array}{ |c| c | c | } \hline \tt{SN}& \tt{STATEMENTS} & \tt{REASONS}\\ \hline 1& \sf{In \: \triangle ^{s} \:AOB \: and \: COD } \\ \sf{(i)}& \sf{ \angle \: OAB = \angle \: OCD\: (A)}& \sf{AB \parallel \: DC \: and \: alternate \: angles} \\ \sf{(ii)} &\sf{AB = DC(S)}& \sf{Opposite \: sides \: of \: a \: parallelogram} \\ \sf{(iii)} &\sf{ \angle \: OBA= \angle \: ODC(A)} &\sf{AB \parallel \:DC \: and \: alternate \: angles} \\ \sf{(iv)}& \sf{ \triangle \:AOB\cong \triangle \: COD}& \sf{A.S.A \: axiom}\\ \hline 2.& \sf{AO = OC \: and \: BO = OD}& \sf{Corresponding \: sides \: of \: congruent \: triangle}\\ \hline 3.& \sf{AC \: and \: BD \: bisect \: each \: other \: at \: O}& \sf{From \: statement \: (2)}\\ \\ \hline\end{array}. Proved ✔$

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