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Solnce55 [7]
3 years ago
9

3/5 of a pound of clay to make a bowl. How many bowls could the potter make from 10 pounds of clay?

Mathematics
1 answer:
Luden [163]3 years ago
5 0

Step-by-step explanation:

3/5 pound of clay = 1 bowl

=> 10 pounds of clay = 10 / (3/5) = 16.666 bowls

Hence the potter can make 16 bowls.

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In the figure, r//s
lys-0071 [83]
M < 2 = m < 6...corresponding angles

m < 5 = m < 8....vertical angles are congruent
5 0
3 years ago
Read 2 more answers
Giselle works as a carpenter and as a blacksmith.
Usimov [2.4K]

Answer:

34.5 hours as carpenter or 27.6 hours for blacksmith (Not sure about this sorry)

Step-by-step explanation:

690 ÷ 20 and 690 ÷ 25

8 0
3 years ago
How to do 3/2b+1/5b=17 ?
guajiro [1.7K]

Answer:

b = 10

Explanation:

Lets start by combining like terms (b):

3/2b + 1/5b

to combine these fractions you must get them to both have the same denominator:

3/2 · 5/5 = 15/10     multiply top and bottom by other fractions denominator

1/5 · 2/2 = 2/10       multiply top and bottom by other fractions denominator

15/10 + 2/10 = 17/10

17/10b = 17

Now we want to get the b to be by itself, so lets first multiply both sides by 10:

17b = 170

Now lets divide both sides by 17:

b = 10

Hope this helped!

7 0
3 years ago
Read 2 more answers
Determine whether the set of all linear combinations of the following set of vector in R^3 is a line or a plane or all of R^3.a.
Temka [501]

Answer:

a. Line

b. Plane

c. All of R^3

Step-by-step explanation:

In order to answer this question, we need to study the linear independence between the vectors :

1 - A set of three linearly independent vectors in R^3 generates R^3.

2 - A set of two linearly independent vectors in R^3 generates a plane.

3 - A set of one vector in R^3 generates a line.

The next step to answer this question is to analyze the independence between the vectors of each set. We can do this by putting the vectors into the row of a R^(3x3) matrix. Then, by working out with the matrix we will find how many linearly independent vectors the set has :

a. Let's put the vectors into the rows of a matrix :

\left[\begin{array}{ccc}-2&5&-3\\6&-15&9\\-10&25&-15\end{array}\right] ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix  ⇒

\left[\begin{array}{ccc}-2&5&-3\\0&0&0\\0&0&0\end{array}\right]

We find that the second vector is a linear combination from the first and the third one (in fact, the second vector is the first vector multiply by -3).

We also find that the third vector is a linear combination from the first and the second one (in fact, the third vector is the first vector multiply by 5).

At the end, we only have one vector in R^3 ⇒ The set of all linear combinations of the set a. is a line in R^3.

b. Again, let's put the vectors into the rows of a matrix :

\left[\begin{array}{ccc}1&2&0\\1&1&1\\4&5&3\end{array}\right] ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

\left[\begin{array}{ccc}1&1&1\\0&1&-1\\0&0&0\end{array}\right]

We find that there are only two linearly independent vectors in the set so the set of all linear combinations of the set b. is a plane (in fact, the third vector is equivalent to the first vector plus three times the second vector).

c. Finally :

\left[\begin{array}{ccc}0&0&3\\0&1&2\\1&1&0\end{array}\right] ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

\left[\begin{array}{ccc}1&1&0\\0&1&2\\0&0&3\end{array}\right]

The set is linearly independent so the set of all linear combination of the set c. is all of R^3.

4 0
2 years ago
If x=-2 substitute the value of x into the expression and simplify
uranmaximum [27]

Answer:

-17

Step-by-step explanation:

the expression is 6x-5

Substituting x=-2

6(-2)-5

(-12)-5=-17

7 0
3 years ago
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