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Solnce55 [7]
3 years ago
9

3/5 of a pound of clay to make a bowl. How many bowls could the potter make from 10 pounds of clay?

Mathematics
1 answer:
Luden [163]3 years ago
5 0

Step-by-step explanation:

3/5 pound of clay = 1 bowl

=> 10 pounds of clay = 10 / (3/5) = 16.666 bowls

Hence the potter can make 16 bowls.

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Whats balance fe+30^2 >fe^2O^3
blsea [12.9K]

Answer:

You are given:

4Fe+3O_2 -> 2Fe_2O_3

4:Fe:4

6:O_2:6

You actually have the same number of Fe on both sides, The same is true for O_2 so yes this equation is properly balanced.

For added benefit consider the following equation:

CH_4+O_2-> CO_2+2H_2O

ASK: Is this equation balanced? Quick answer: No

ASK: So how do we know and how do we then balance it?

DO: Count the number of each atom type you have on each side of the equation:

1:C:1

4:H:4

2:O:4

As you can see everything is balanced except for O To balance O we can simply add a coefficient of 2 in front of O_2 on the left side which would result in 4 O atoms:

CH_4+color(red)(2)O_2-> CO_2+2H_2O

1:C:1

4:H:4

4:O:4

Everything is now balanced.

Step-by-step explanation:

5 0
2 years ago
An article in Fire Technology investigated two different foam-expanding agents that can be used in the nozzles of firefighting s
UNO [17]

Answer:

Step-by-step explanation:

Hello!

The objective of this experiment is to test if two different foam-expanding agents have the same foam expansion capacity

Sample 1 (aqueous film forming foam)

n₁= 5

X[bar]₁= 4.7

S₁= 0.6

Sample 2 (alcohol-type concentrates )

n₂= 5

X[bar]₂= 6.8

S₂= 0.8

Both variables have a normal distribution and σ₁²= σ₂²= σ²= ?

The statistic to use to make the estimation and the hypothesis test is the t-statistic for independent samples.:

t= \frac{(X[bar]_1 - X[bar]_2) - (mu_1 - mu_2)}{Sa*\sqrt{\frac{1}{n_1} + \frac{1}{n_2 } } }

a) 95% CI

(X[bar]_1 - X[bar]_2) ± t_{n_1 + n_2 - 2}*Sa* \sqrt{\frac{1}{n_1}+\frac{1}{n_2} }

Sa²= \frac{(n_1-1)S_1^2 + (n_2-1)S_2^2}{n_1 + n_2 - 2}= \frac{(5-1)0.36 + (5-1)0.64}{5 + 5 - 2}= 0.5

Sa= 0.707ç

t_{n_1 + n_2 -2: 1 - \alpha /2} = t_{8; 0.975} = 2.306

(4.7-6.9) ± 2.306* (0.707\sqrt{\frac{1}{5}+\frac{1}{5} })

[-4.78; 0.38]

With a 95% confidence level you expect that the interval [-4.78; 0.38] will contain the population mean of the expansion capacity of both agents.

b.

The hypothesis is:

H₀: μ₁ - μ₂= 0

H₁: μ₁ - μ₂≠ 0

α: 0.05

The interval contains the cero, so the decision is to reject the null hypothesis.

<u>Complete question</u>

a. Find a 95% confidence interval on the difference in mean foam expansion of these two agents.

b. Based on the confidence interval, is there evidence to support the claim that there is no difference in mean foam expansion of these two agents?

8 0
3 years ago
Pls help me tysm if you can!!
Mice21 [21]
The answer is 0.687.
8 0
3 years ago
Read 2 more answers
A line with a slope of 2 passes through the point (3,9).
Licemer1 [7]

Answer:

y-9=2(x-3)

Step-by-step explanation:

The point-slope formula is: y-y1=m(x-x1)

y1 and x1 is where you plug in the coordinate and m is the slope.

y1 is the second number of the coordinate (x, y)

So, y1 is 9 in this case

x1 is the first number of the coordinate (x, y)

So x1 is 3 in this case

Do you get it or do I need to explain further?

4 0
3 years ago
Simplify<br><br> 5-2(6+4m)+5m<br><br><br> Can anyone help me solve this thanks!
harina [27]
1. 3(6+4m) + 5m
2. Distribute the 3 to the inside of the brackets = 18 + 12m + 5m
3. 17m+18

Hope this helps!
8 0
3 years ago
Read 2 more answers
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