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r-ruslan [8.4K]
4 years ago
9

Need help fast!!!!!!!!

Mathematics
1 answer:
Kamila [148]4 years ago
4 0
C. 2/3; reduction
have a good day
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An aquifer holds 146,000 cubic feet of water. Water exits through a well at a steady rate of 500 cubic feet per day, and the aqu
m_a_m_a [10]

Answer:

The value of x = 100  ft^3/ day

Step-by-step explanation:

We need to look at what amount of water comes in and what amount of water leaves

What comes in:  x ft^3/ day

What leaves : 500x ft^3/ day

We start with 146 000 ft^3

Water in tank = what we start with + what comes in - what leaves

water in tank = 146000 + x*d - 500*d  where d is the number of days

After 365 days , the tank has 0 ft^3 of water

0  = 146000 + x*365 - 500*365

Multiply

0 = 146000 + 365x - 182500

Combine like terms

0 = -36500+365x

Add 36500 to each side

36500 = 36500-36500+365x

36500 = 365x

Divide by 365

36500/365 = 365x/365

100=x

The value of x = 100


8 0
3 years ago
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What answer is correct? The audio is just reading the question.
RSB [31]

Answer:

its 7

Step-by-step explanation:

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Two days after a biology experiment there was 49 million bacteria present. Four days after the experiment there was 600.25 milli
nataly862011 [7]

Answer:

y=Ae^(1.25t)

Step-by-step explanation:

From the expression  y=Ae^kt

After two days of the experiment, y = 49 million, t=2

After four days of the experiment, y= 600.25 million, t=4

A is the amount of bacteria present at time zero  and t is the time after the experiment (in days)

At t=2 and y =49

 49=Ae^2k…………….. (1)

At t=4 and y = 600.25

600.25=Ae^4k………… (2)

Divide equation (2) by equation (1)

600.25/49=(Ae^4k)/(Ae^2k )

12.25=e^2k

Take natural log of both sides

ln⁡(12.25) =2k

2.505⁡ =2k

k=1.25

The exponential equation that models this situation is y=Ae^(1.25t)

8 0
3 years ago
What number is 15% of 120
Sergio039 [100]

Answer:

18

Step-by-step explanation:

120 times .15 to get 18

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Who wants to help I really really need it ❤️
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It would be 8 to the 8th power
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