Answer:
Least number of bus require for trip = 5 buses (Approx)
Step-by-step explanation:
Given:
Total number of classes = 9
Number of student in each class = 25
Number of teacher = 4
Number of chaperones = Double of teacher
Bus hold = 45 people
Find:
Least number of bus require for trip
Computation:
Total number of student = 9 × 25
Total number of student = 225
Number of chaperones = 4 × 2
Number of chaperones = 8
Total people = 225 + 8 + 4
Total people = 237
Least number of bus require for trip = Total people / Bus hold
Least number of bus require for trip = 237 / 45
Least number of bus require for trip = 5.266
Least number of bus require for trip = 5 buses (Approx)
The absolute value is the distance from 0, so it would be 4 and -4
Answer:
the answer is 11%
Step-by-step explanation:
this is because
27/30x100=90
which is 90
but the difference between 100 and 90 is 10
so its 10% but its closer to 11%
so yeah
i am not sure if its correct
Hello from MrBillDoesMath!
Answer: infinite solutions
Discussion: I did a double take on this one but the left hand is
a + 3 + 2a = 3a +3
and the right hand side is
-1 + 3a + 4 = 3a + (4-1) = 3a + 3
The left and right sides of the equation are identical for all "a", i.e. for infinitely many "a" values.
Regards, MrB.
