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egoroff_w [7]
3 years ago
12

ASAP Can someone please helppp

Mathematics
1 answer:
vfiekz [6]3 years ago
4 0

Answer:

Option 4

Step-by-step explanation:

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Which would be the most appropriate subject line for
lesantik [10]

Answer:

answer choice B.......Cell phones as an educational tool

Step-by-step explanation:

self explanatory

6 0
3 years ago
What is the least common denominator of the fractions 2/3 and 3/5? HELP PLEASE
grigory [225]

Answer:what is the least common denominator of the fractions 2/3 and 3/5? HELP PLEASE

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Kyle is shopping for his favorite
nalin [4]

Answer:

The 9 ounce box is the better deal, and Kyle will save 2 cents.

Step-by-step explanation:

First, you should find how much 1 once would cost in the 9 ounce box.

Do 2.52 ÷ 9 = x

x = 0.28

This means that in the <u>9 ounce box, one ounce costs 28 cents</u>.

Now, find how much one once would cost in the 12 ounce box.

3.60 ÷ 12 = x

x = 0.30

This means that in the <u>12 ounce box, one ounce costs 30 cents</u>.

This means that the 9 ounce box is a better deal, because it costs less per ounce.

0.30 - 0.28 = 0.02. This means there is a 2 cent difference in their prices per ounce.

So, Kyle should choose the 9 ounce box, and he will save 2 cents per box.

5 0
2 years ago
Explain how to evaluate simplify and convert to radical form (x^3/8)^3/4
Vaselesa [24]

Answer:

(x^\frac{3}{8})^\frac{3}{4}  = \sqrt[32]{x^9}

Step-by-step explanation:

Given

(x^\frac{3}{8})^\frac{3}{4}

Required

Convert to radical form

(x^\frac{3}{8})^\frac{3}{4}

Evaluate the exponents

(x^\frac{3}{8})^\frac{3}{4} = x^\frac{3*3}{8*4}

(x^\frac{3}{8})^\frac{3}{4} = x^\frac{9}{32}

Split the exponent

(x^\frac{3}{8})^\frac{3}{4} = (x^9)^\frac{1}{32}

Apply the following law of indices

(x^a)^\frac{1}{b} = \sqrt[b]{x^a}

So, we have:

(x^\frac{3}{8})^\frac{3}{4}  = \sqrt[32]{x^9}

3 0
3 years ago
Question 2 please fas
Len [333]

Answer:

a = 3, b = 2

Step-by-step explanation:

It is given that both the polynomials are equal.

Therefore, h(x) = k(x)

{x}^{3}  + (a + b) {x}^{2}  - 4x + 2 \\  =  {x}^{3}  + 5 {x}^{2}  - (2a - b)x + 2 \\  \\ equating \: like \: terms \: on \: both \: sides \\ (a + b) {x}^{2}  = 5 {x}^{2}   \\  \implies \: a + b = 5.....(1) \\  \\  - (2a - b)x =  - 4x \\ 2a - b = 4....(2) \\  \\ adding \: equations \: (1) \: and \: (2) \\  \\ 3a = 9 \\   \implies \: a =  \frac{9}{3}  \\   \huge \red{ \boxed{\implies \: a = 3}} \\  \\ substituting \: a = 3 \: in \: equation \: (1) \\ 3 + b = 5 \\   \implies \: b = 5 - 3 \\ \huge \purple{ \boxed{ \implies  b = 2}}

5 0
3 years ago
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