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3 years ago

Irene además de 4 pantalones y 6 camisetas tiene 3 gorras cuántas indumentarias de pantalón camiseta gorra puede llevar

Mathematics

1 answer:

Sidana [21]3 years ago

3 0

Answer:

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Graph the equation

Lisa [10]

To find the root, replace y with 0
X^2-12x+35=0
A=1 B=-12 C=35
B^2-4ac=(-12)^2 -4(1)(35)
=144 -140
=4

x=(-b+/- square root of b^2 -4ac) /over/ (2a)
Plug in the numbers
x=-(-12) sqr (-12)^2 4(1)(35) / (2)(1)
X=12 +/-sqr 4 / 2
Positive outcome
x=12 + sqr 4 / 2
x=12+2/2
x=7 <— this one
Negative outcome
x=12-2i/2
x=6-i
Vertex: (6,-1)

8 0

2 years ago

What is the solution to the equation below?

MakcuM [25]

Answer:

X=4

Step-by-step explanation:

The solution is in the file

5 0

2 years ago

Read 2 more answers

The measure of the vertex angle of an isosceles triangle is 92. Find the measure of a base angle

Andrej [43]

Answer:

44°

Step-by-step explanation:

The sum of the angles in a triangle = 180°

In an isosceles triangle the base angles are equal, thus

base angle = $\frac{180-92}{2}$ = $\frac{88}{2}$ = 44°

6 0

3 years ago

Using compatible numbers to find each quotient. 18.2 divided by 11

UNO [17]

It is 166 just do some side math if you can and I think youtline get it ok but that's what I got if someone eles gets somthing eles matey listen to them

5 0

3 years ago

A population has a standard deviation of 5.5. What is the standard error of the sampling distribution if the sample size is 81?

VladimirAG [237]

Answer:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

Step-by-step explanation:

For this case we know the population deviation given by:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

4 0

3 years ago

Irene además de 4 pantalones y 6 camisetas tiene 3 gorras cuántas indumentarias de pantalón camiseta gorra puede llevar​

Irene además de 4 pantalones y 6 camisetas tiene 3 gorras cuántas indumentarias de pantalón camiseta gorra puede llevar