3 years ago

Can someone help me please

Mathematics

1 answer:

zvonat [6]3 years ago

8 0

Step-by-step explanation:

you can follow the same procedure for others

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Step-by-step explanation:

Given value:

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$\to x^2+y^2= 16 \cos^2 t +16 \sin^2 t\\\\\to x^2+y^2= 16 (\cos^2 t +\sin^2 t)\\\\\therefore (\cos^2 t +\sin^2 t =1)\\\\\to x^2+y^2= 16 (1)\\\\\to x^2+y^2= 16\\\\\to z=1$

So, the curve $r(t) = 4 \cos (t)i + 4 sin(t)j + k$ is basically a circle, which is defined in the attachment file.

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