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Sophie [7]
3 years ago
6

Nevaeh is decorating the Christmas tree. She has 85 red bulbs, 76 green bulbs, 49 yellow bulbs, and 52 blue bulbs.

Mathematics
1 answer:
vodka [1.7K]3 years ago
5 0

Answer:

A) Red and Blue Bulbs

B) 262 lightbulbs.

Step-by-step explanation:

A) red and blue = 85+52=137

Yellow and green = 76+49=125

Answer to A is Red and Blue bulbs

Bulbs in all: We already know from A that there are 137 and 125 so 137+125 is 262.

Hope this helps plz hit the crown :D

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Write the point from of the equation for a line that passes through (6,—1) with a slope of 2
Paraphin [41]

Answer:

y = 2x-13

Step-by-step explanation:

The equation for a line is

y = mx+b where m is the slope and b is the y intercept

y = 2x+b

We know a point so we have a y and an x, so we can solve for b

-1 = 2(6) +b

-1 =12+b

Subtract 12 from each side

-1-12 = 12-12+b

-13 =b

Substitute this into y = 2x+b

y = 2x-13

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3 years ago
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Is -13x+3 increasing or decreasing negative or positive slope????
Dafna11 [192]

-13x + 3 is decreasing and has a negative slope.

6 0
3 years ago
If I work two days and get paid 7.25 an hour how much is that
PtichkaEL [24]
The answer is 348.00. You have to multiply 7.25 by 24 and then use the product and double it.
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3 years ago
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What is the value of x in the equation 3 minus 2 x = negative 1.5 x? –6 –2 2 6
olga_2 [115]

Answer:

x=118.25

Step-by-step explanation:

3−2x=−1.5−6−226

3+−2x=−1.5+−6+−226

−2x+3=(−1.5+−6+−226)(Combine Like Terms)

−2x+3=−233.5

−2x+3=−233.5

Step 2: Subtract 3 from both sides.

−2x+3−3=−233.5−3

−2x=−236.5

Step 3: Divide both sides by -2.

−2x

−2

=

−236.5

−2

x=118.25

4 0
3 years ago
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Determine an equation of a Quadratic function
Pepsi [2]

Answer:

y = -4x² + 32x - 48

Step-by-step explanation:

The standard form of a quadratic equation is  

y = ax² + bx + c

We must find the equation that passes through the points:

(2, 0), (6,0), and (3, 12)

We can substitute these values and get three equations in three unknowns.

0 = a(2²) + b(2) + c

0 = a(6²) + b(6) + c

12 = a(3²) + b(3) + c

We can simplify these to get the system of equations:

(1)   0 =    4a + 2b + c

(2)  0 = 36a + 6b + c

(3) 12 =   9a + 3b + c

Eliminate c from equations (1) and (2). Subtract (1) from (2).

(4) 0 = 32a + 4b

Eliminate c from equations (2) and (3). Subtract (3) from (2).

(5) -12 = 27a - 3b

Simplify equations (4) and (5).

(6)  0 = 8a + b

(7) -4 = 9a  - b

Eliminate b by adding equations (6) and (7).

(8) a = -4

Substitute (4) into (6).

    0 = -32 + b

(9) b =  32

Substitute a and b into (1)

0 = 4(-4) + 2(32) + c

0 = -16 + 64 + c

0 = 48 + c

c = -48

The coefficients are

a= -4, b = 32, c = -48

The quadratic equation is

y = -4x² + 32x - 48

The diagram below shows the graph of your quadratic equation and the three points through which it passes.

4 0
3 years ago
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