Answer:
The proportion of students whose height are lower than Darnell's height is 71.57%
Step-by-step explanation:
The complete question is:
A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 centimeters. Darnel is a middle school student with a height of 161.4cm.
What proportion of proportion of students height are lower than Darnell's height.
Answer:
We first calculate the z-score corresponding to Darnell's height using:

We substitute x=161.4 ,
, and
to get:

From the normal distribution table, we read 0.5 under 7.
The corresponding area is 0.7157
Therefore the proportion of students whose height are lower than Darnell's height is 71.57%
Answer:
the last three
Step-by-step explanation:
cuz im big brains like that
Answer:
-35
Step-by-step explanation:
it is going backwards by -7 so 5x-7 = -35
Answer:
81.12 cm²
Step-by-step explanation:
The area for a semicircle can be figured with this formula: (πr²)/2. The triangle's area formula is bh/2.
(3.14 * 4²)/2 + (14 * 8)/2 <em>(Work the operations in parentheses first.)</em>
(3.14 * 16)/2 + 112/2
50.24/2 + 112/2 (<em>Divide 50.24 by 2. Do the same for 112.)</em>
25.12 + 56 (<em>Add 25.12 & 56.)</em>
81.12 cm²
The area of the figure is 81.12 cm².