Answer:
y +2 = 4(x -3)
Step-by-step explanation:
Point-slope form of the equation of a line with slope m through point (h, k) is ...
y -k = m(x -h)
For m = 4 and (h, k) = (3, -2), the equation is ...
y +2 = 4(x -3) . . . . . matches the first choice
Answer:
5x^2+22x-12 x cannot be -5, -4, -2
(x+5)(x+4)(x+2)
Step-by-step explanation:
In order to solve this, your denominator must be the same. Let's start by writing out the two different quadratic formulas:
x^2 + 6x + 8 <-- This should factor out to (x+4)(x+2)
x^2 + 7x + 10 <-- This should factor out to (x+5)(x+2)
Now that you have factored out the two quadratics, plug them into the equation.
5x - 3
(x+4)(x+2) (x+5)(x+2)
Now as we know, -2 cannot be x because it will turn the entire equation undefined. Multiple top and bottom with (x+5) on the right side and (x+4) on the left side.
5x (x+5) - 3(x+4)
(x+5)(x+4)(x+2) (x+5)(x+4)(x+2)
Focus on the top. 5x(x+5) will turn out to be 5x^2+25x. 3(x+4) will turn out to be 3x+12. Combine the two equations because now they are equal to each other and do the subtraction:
5x^2+25x - (3x+12) = 5x^2+22x-12 x cannot be -5, -4, -2
(x+5)(x+4)(x+2) (x+5)(x+4)(x+2)
5/6= c/9
Cross mutiple. 5* 9= 45 . c*6
45= 6c
divide by 6 for 45 and 6c
45/6= 6c/6
45/6= c
Reduce 45/6. Divide by 3
45/3, 6/3
15/2= c
Answer: c= 15/2 or in decimal form , c= 7.5
Answer:
I would say the last one, bc b Is negative correct?
