Here's how you solve this. So, x+y=2, right? Let's isolate x. x+y-y=2-y. x=2-y. NOW, if x=2-y, in 3x+2y=5, we can REPLACE x with 2-y and use it to solve for y! 3x+2y=5. 3(2-y)+2y=5. (3*2)+(3*-y)+2y=5. 6+(-3y)+2y=5. 6+(-y)=5. 6+(-y)-6=5-6. -y=-1. -y/-1=-1/-1. y=1.
So, if y=1, we can substitute that back into either equation--but let's go with the easier one, x+y=2. x+1=2. x+1-1=2-1. x=1. 1+1=2, so that works; let's check the other equation. 3(1)+2(1)=5. 3+2=5. 5=5. That's correct!
Answer: x=1, y=1
Can you post the provable question
3/11 as a decimal is .27 repeating that means it has a line over the two and the seven but if you want to round it would be .3
Answer:
Distance = 73 m
Step-by-step explanation:
Given that,
The length of a rectangle = 48 m
The width of a rectangle = 55 m
We need to find the diagonal distance. We can use the Pythagoras theorem to find it.
So, the required distance is equal to 73 m.
Answer:
i think its 60
Step-by-step explanation:
base times height then divide by 2
