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ki77a [65]
3 years ago
11

2. Write the equation of the line that passes through point (8, -2) and parallel to line y =-1/4x-2

Mathematics
1 answer:
Ludmilka [50]3 years ago
5 0

Answer:

y = -1/4x

Step-by-step explanation:

If two lines are parallel to each other, they have the same slope.

The first line is y = -1/4x - 2. Its slope is -1/4. A line parallel to this one will also have a slope of -1/4.

Plug this value (-1/4) into your standard point-slope equation of y = mx + b.

y = -1/4x + b

To find b, we want to plug in a value that we know is on this line: in this case, it is (8, -2). Plug in the x and y values into the x and y of the standard equation.

-2 = -1/4(8) + b

To find b, multiply the slope and the input of x (8)

-2 = -2 + b

Now, add 2 to both sides to isolate b.

0 = b

Plug this into your standard equation.

y = -1/4x

This equation is parallel to your given equation (y = -1/4x - 2) and contains point (8, -2)

Hope this helps!

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Dmitry [639]

Answer:

Explanation:

Given:

The equation describing the forest wood biomass per hectare as a function of plantation age t is:

y(t) = 5 + 0.005t^2 + 0.024t^3 − 0.0045t^4

The equation that describes the annual growth in wood biomass is:

y ′ (t) = 0.01t + 0.072t^2 - 0.018t^3

To find:

a) The year the annual growth achieved its highest possible value

b) when does y ′ (t) achieve its highest value?

a)

To determine the year the highest possible value was achieved, we will set the derivative y'(t) to zero. The values of t will be substituted into the second derivative to get the highest value

\begin{gathered} 0\text{ = 0.01t + 0.072t}^2\text{ - 0.018t}^3 \\ using\text{ a graphing tool,} \\ t\text{  = -0.1343} \\ \text{t = 0} \\ t\text{ = 4.1343} \\  \\ Since\text{ we can't have time as a negative value, t = 0 or t = 4.1343} \end{gathered}\begin{gathered} To\text{ ascertain which is the maximum, we take a second derivative} \\ y^{\prime}\text{'\lparen t\rparen = 0.01 + 0.144t - 0.054t}^2 \\  \\ substitute\text{ t = 0 and t = 4.13 respectively} \\ when\text{ t = 0 } \\ y^{\prime}\text{'\lparen t\rparen= 0.01 + 0.144\lparen0\rparen - 0.054\lparen0\rparen}^2 \\ y^{\prime}\text{'\lparen t\rparen= 0.01 + 0 - 0} \\ y^{\prime}\text{'\lparen t\rparen= 0.01 > 0} \\  \\ y^{\prime}\text{'\lparen t\rparen= 0.01 + 0.144\lparen4.13\rparen - 0.054\lparen4.13\rparen}^2 \\ y^{\prime}\text{'\lparen t\rparen= -0.316 < 0} \\  \\ if\text{ }y^{\prime}\text{'\lparen t\rparen > 0 , then it is minimum, } \\ if\text{ }y^{\prime}\text{'\lparen t\rparen < 0, then it is maximum} \end{gathered}

SInce t = 4.13, gives y ′' (t) = -0.316 (< 0). This makes it the maximum value of t

The year the annual growth achieved its highest possible value to the nearest whole number will be

year 4

b) y ′ (t) will achieve its highest value, when we substitute the value of t that gives into the initial function.

Initial function: y(t) = 5 + 0.005t^2 + 0.024t^3 − 0.0045t^4

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6 0
2 years ago
2. The table shows distance, y, that Mario runs in x minutes.
grigory [225]

Answer:

Equation: y = ⅐x

Rate of change: ⅐

Distance = 10 miles

Step-by-step explanation:

Given

The information in the above table

Solving (a): The equation

To get the equation, we need to first calculate the slope (m)

Take any two corresponding values of x and y

(x1,y1) = (7,1)

(x2,y2) = (21,3)

m = (y2 - y1)/(x2 - x1)

m = (3 - 1)/(21 - 7)

m = 2/14

m = ⅐

The equation is calculated using

y - y1 = m(x - x1)

Substitute values for m, x1 and y1

y - 1 = ⅐(x - 7)

y - 1 = ⅐x - 1

Add 1 to both sides

y = ⅐x

Solving (b) Rate of change:

The calculated slope in (a) above represents the rate of change.

So:

Rate of change = Slope = ⅐

Solving (c): Distance when time is 70 minutes

This implies that x = 70

Substitute 70 for x in y = ⅐x

y = ⅐ * 70

y = 10 miles

4 0
3 years ago
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asambeis [7]
The answer is number 2, b!
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Katyanochek1 [597]

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3 0
3 years ago
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