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2 years ago

An architect increases the radius of a circle window by 20 percent. By what percent

Mathematics

2 answers:

Butoxors [25]2 years ago

7 0

Answer:

Step-by-step explanation:

For a circle of radius R, the area is written as:

A = pi*R^2

Where pi = 3.14

If we increase the radius by 20%, the new radius will be:

R´ = R + 0.20*R = 1.20*R

The new area will be:

A´ = pi*(1.20*R)^2 = (1.20)^2*pi*R^2

= 1.44*pi*R^2

And pi*R^2 = A, the original area, then_

A´ = 1.44*A = A + 0.44*A

This means that the percentage in which the area increased is:

0.44*100% = 44%

ale4655 [162]2 years ago

6 0

Answer: 44%

Step-by-step explanation:

For a circle of radius R, the area is written as:

A = pi*R^2

Where pi = 3.14

If we increase the radius by 20%, the new radius will be:

R´ = R + 0.20*R = 1.20*R

The new area will be:

A´ = pi*(1.20*R)^2 = (1.20)^2*pi*R^2

= 1.44*pi*R^2

And pi*R^2 = A, the original area, then_

A´ = 1.44*A = A + 0.44*A

This means that the percentage in which the area increased is:

0.44*100% = 44%

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2 years ago

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3 years ago

A farmer wants to build a fence enclosing a rectangular region bordering a river. If the farmer has 500 feet of fencing, find th

Romashka [77]

Answer:

31,250 ft²

Step-by-step explanation:

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3 years ago

Can someone please help I need a clear explanation on how to solve this equation.

nikitadnepr [17]

B = amount of students who chose Bulldog

n = amount of students who chose lion

t = amount of students who chose tiger

so.. "t" chose tiger, ok

"Four times as many students chose Bulldog as chose Tiger"
namely, if "t" chose tiger, then 4 times that many chose Bulldog, thus

b = 4t

"Twice as many students chose Lion as chose Tiger"
namely, if "t" students chose tiger, twice as many chose lion

n = 2t

now, we know a total of 273 students were surveyed, thus

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b+n+t=273\\
\boxed{4t}+\boxed{2t}+t=273
\end{cases}
\\\\\\
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3 years ago

Read 2 more answers

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We have the Trigonometric Identities : secx = 1/cosx; (sinx)^2 + (cosx)^2 = 1;
Then, 1 / (1-secx) = 1 / ( 1 - 1/cosx) = 1 / [(cosx - 1)/cosx] = cosx /
(cosx - 1 ) ;
Similar, 1 / (1+secx) = cosx / (1 + cosx) ;
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3 years ago