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Gnesinka [82]
4 years ago
13

What are the coordinates of the point on the directed line segment from (4, -3)(4,−3) to (9, -8)(9,−8) that partitions the segme

nt into a ratio of 3 to 2?
Mathematics
1 answer:
jekas [21]4 years ago
8 0

Answer:

  (7, -6)

Step-by-step explanation:

You want to find point X on the segment from A to B such that ...

  (X -A)/(B -X) = 3/2

  2(X -A) = 3(B -X) . . . . . . cross multiply

  2X -2A = 3B -3X . . . . . eliminate parentheses

  5X = 2A +3B . . . . . . . . add 3X +2A

  X = (2A +3B)/5 . . . . . . . divide by 5

Filling in the given points for A and B, we have ...

  X = (2(4, -3) +3(9, -8))/5 = (8+27, -6-24)/5 = (35, -30)/5

  X = (7, -6)

The point that divides the segment in the proportions 3:2 is (7, -6).

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pls help me with this if you know it also to explain it thanks Solve the equation -21 + 70n = 77 for n.
gogolik [260]

Answer:

n = 1 2/5

Step-by-step explanation:

-21 + 70n = 77

Add 21 to each side

-21+21 + 70n = 77 +21

70n = 98

Divide each side by 70

70n/70 = 98/70

n =98/70

n = 70/70 +28/70

n = 1 + 2/5

n = 1 2/5

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Answer:

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Step-by-step explanation:

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Write an equation for the translation of y=3/x with asymptotes of x=7 and y=-5
Sergeeva-Olga [200]

Answer:

y = (3 / (x-7)) - 5

Step-by-step explanation:

The original equation has the asymptotes at x = 0 and y = 0.

We want to translate to the right by 7 units so that the asymptote is at x = 7 and downwards 5 units so that the asymptote is y = -5.

Now, in the first case, to move it to the right, you must subtract 7 from the independent variable (i.e. x)

And in the second case, to move a function down 5 units, subtract 5 units from the entire function.

Applying the above, the new function would be:

y = (3 / (x-7)) - 5

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Answer:

The answer is 15 weeks.

Step-by-step explanation:

Hope that helps. :)

Pls mark me a Brainliest

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