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Tom [10]
3 years ago
11

According to the National Center for Health​ Statistics, in​ 1990, 28% of babies in the United States were born to parents who w

ere not married. Throughout the​ 1990s, this increased by approximately 0.6% per year. If this trend​ continues, in which year will 31% of babies be born out of​ wedlock?
Mathematics
1 answer:
svlad2 [7]3 years ago
6 0

Answer:

The year is  b =  1995

Step-by-step explanation:

From the question we are told that

   The percentage of the number of babies born out of wedlock in 1990 is  k = 28%

    The percentage by which the number increase per year is  i = 0.6%

     The percentage of of the number of babies born out of wedlock considered is  a = 31%

Generally the difference in between the percentage in 1990 and the percentage considered is  

       d =  a - k

=>    d =  31 - 28

=>   d =  3\%

Generally the number of year require for the percentage to be equal  to  31%  is mathematically represented as

       n = \frac{3\%}{0.6\%}

=>     n = 5\ years

Generally the year which the considered percentage will be attained is  

    b =  1990 + n

=> b =  1990 + 5

=> b =  1995

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Step-by-step explanation:

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- Make the relation for Q:

                                       Q = C*e^(-r*t)

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                                       Q(0) = Q_o

                                       Q_o = C*e^(-r*0)

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                                        r = 0.000120968          

- Hence, our expression for Q(t) would be:

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