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Tom [10]
3 years ago
11

According to the National Center for Health​ Statistics, in​ 1990, 28% of babies in the United States were born to parents who w

ere not married. Throughout the​ 1990s, this increased by approximately 0.6% per year. If this trend​ continues, in which year will 31% of babies be born out of​ wedlock?
Mathematics
1 answer:
svlad2 [7]3 years ago
6 0

Answer:

The year is  b =  1995

Step-by-step explanation:

From the question we are told that

   The percentage of the number of babies born out of wedlock in 1990 is  k = 28%

    The percentage by which the number increase per year is  i = 0.6%

     The percentage of of the number of babies born out of wedlock considered is  a = 31%

Generally the difference in between the percentage in 1990 and the percentage considered is  

       d =  a - k

=>    d =  31 - 28

=>   d =  3\%

Generally the number of year require for the percentage to be equal  to  31%  is mathematically represented as

       n = \frac{3\%}{0.6\%}

=>     n = 5\ years

Generally the year which the considered percentage will be attained is  

    b =  1990 + n

=> b =  1990 + 5

=> b =  1995

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Answer:

f(-4) = 5

Step-by-step explanation:

Explanation of

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When the x in f(x) is less than -3 than f(x) = 5

When the x in f(x) is greater than -3 but less than 4 then f(x) = 2x² - 4

When the x in f(x) is greater than 4 than f(x) = 1 - 6x

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Now that we know this lets look back at the question.

We want to find f(-4).

Looking at the piece wise function we see that f(-4) follow x < -3 as "x" or -4 is less than -3. When x is less than -3, f(x) = 5, hence f(-4) = 5

     

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2 years ago
The points (7,r) and (8,9) fall on a line with a slope of 5. What is the value of r?
mrs_skeptik [129]

Answer:

r = 4

Step-by-step explanation:

Calculate the slope m using the slope formula and equate to 5

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with (x₁, y₁ ) = (7, r ) and (x₂, y₂ ) = (8, 9)

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r = 4

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1/2

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The roots of the equation f(x) = x^2 - 93987 are x = √93987 and x = -√93987

<h3>What are quadratic equations?</h3>

Quadratic equations are equations that have a second degree and have the standard form of ax^2 + bx + c = 0, where a, b and c are constants and the variable a does not equal 0

<h3>How to determine the other roots of the equation?</h3>

The equation of the function is given as:

f(x) = x^2 - 93987

The above equation is a quadratic equation

Express the equation as a difference of two squares

f(x) = (x - √93987)(x + √93987)

Set the equation of the function to 0

(x - √93987)(x + √93987) = 0

Split the factors of the above function equation as follows

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Solve for x in the above equations

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Hence, the roots of the equation f(x) = x^2 - 93987 are x = √93987 and x = -√93987

Read more about roots of equation at

brainly.com/question/776122

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