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zalisa [80]
3 years ago
6

What is the difference between advanced calculus and real analysis?

Mathematics
1 answer:
eduard3 years ago
8 0
<span>The content of any course depends on where you take it--- even two courses with the title "real analysis" at different schools can cover different material (or the same material, but at different levels of depth).

But yeah, generally speaking, "real analysis" and "advanced calculus" are synonyms. Schools never offer courses with *both* names, and whichever one they do offer, it is probably a class that covers the subject matter of calculus, but in a way that emphasizes the logical structure of the material (in particular, precise definitions and proofs) over just doing calculation.

My impression is that "advanced calculus" is an "older" name for this topic, and that "real analysis" is a somewhat "newer" name for the same topic. At least, most textbooks currently written in this area seem to have titles with "real analysis" in them, and titles including the phrase "advanced calculus" are less common. (There are a number of popular books with "advanced calculus" in the title, but all of the ones I've seen or used are reprints/updates of books originally written decades ago.)

There have been similar shifts in other course names. What is mostly called "complex analysis" now in course titles and textbooks, used to be called "function theory" (sometimes "analytic function theory" or "complex function theory"), or "complex variables". You still see some courses and textbooks with "variables" in the title, but like "advanced calculus", it seems to be on the way out, and not on the way in. The trend seems to be toward "complex analysis."  hope it helps

</span>
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Answer:

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Step-by-step explanation:

2(6k+8)-6k=4

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sukhopar [10]

Answer:

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Step-by-step explanation:

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The time can be calculated by dividing the distance by the speed for each section.

The distance in the shore and in the water depends on when the lifeguard gets in the water. We use the variable x to model this, as seen in the picture attached.

Then, the distance in the shore is d_b=x and the distance swimming can be calculated using the Pithagorean theorem:

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Then, the time (speed divided by distance) is:

t=d_b/v_b+d_s/v_s\\\\t=x/4+\sqrt{x^2-120x+5200}/1.1

To optimize this function we have to derive and equal to zero:

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x

As d_b=x, the lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

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