Answer: $195,000.00
Step-by-step explanation:
6/100 = 11700
100/100 = x
6/100(x)=11700
x = 11700 / (6/100)
= 11700 * 100/6
= 195000
No because the sum of any two sides has to be greater than the third side and 5 plus 2 is not greater than 8
Answer: 45%
Step-by-step explanation: To write a fraction as a percent, first remember that a percent is a ratio of a number to 100. If we want to write 9/20 as a percent, we will need to find a fraction equivalent to 9/20 that has a 100 in the denominator. We can do this by setting up a proportion.
= 
Now, we can use cross products to find the missing value.
900 = 20n
÷20 ÷20 ← <em>divide by 20 on both sides</em>
<em> 45 = n</em>
Therefore, 9/20 is equal to 45 over 100 or 45%.
<u>___________________________________________________</u>
Answer: 0.45
Step-by-step explanation: In order to write 9/20 as a decimal, we need to find a fraction equivalent to 9/20 with a 100 in the denominator. Notice that if we multiply both the numerator of 9/20 by 5, we get the equivalent fraction 45/100 which we can now write as a decimal. Remember that the hundredths place is two places to the right of the decimal point. So, we can write 45/100 as 0.45.
Therefore, 9/20 is equivalent to 0.45.
1 counter can represent 3 the other can represent 2. 3x2=6
1 counter can represent 1 the other can represent 6. 1x6=6
1 counter can represent 3 the other can represent 3. 3+3=6
1 counter can represent 2 the other can represent 12. 12 divided by 2=6
1 counter can represent 36 the other can represent 6. 36 divided by 6=6
1 counter can represent 9 the other can represent 3. 9-3=6
Hope these helped :)
Answer: b. The sampling distribution of the proportion of damaged trees is approximately Normal
Step-by-step explanation:
The sample mean is an unbiased estimator of the true (unknown) population mean and The sampling distribution shows how the sample mean will vary among repeated samples. In the case above the samples are selected at random from a normally distributed population, and the number of samples selected (n=100) is a bit large therefore the sampling distribution will be approximately normal.