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Bad White [126]
3 years ago
14

What is 5x + 8x2 + 32x + 17x2​

Mathematics
1 answer:
Vika [28.1K]3 years ago
6 0

Answer:

The answer is 37x + 5.

Step-by-step explanation:

5x + 8*2 + 32x + 17*2

37x + 16 + 34

37x +50

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Given the system below: ƒ(x) = 2x g(x) = 2x Which value(s) of x make ƒ(x) = g(x) a true statement? If necessary, you may choose
VLD [36.1K]
All values will make f(x)=f(x) because 2=2
8 0
3 years ago
A single die is rolled twice. The set of 36 equally likely outcomes is {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1),
lana [24]

Answer:

(9)\frac{1}{12}  (10) \frac{1}{12}  (11)\frac{5}{12}  (12)\frac{1}{4}  (13)\frac{1}{6} 14)\frac{5}{36} (15)\frac{1}{12}  (16)0

Step-by-step explanation:

The sample Space of the single die rolled twice is presented below:

{(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6),}.

n(S)=36

(9)Probability of getting two numbers whose sum is 9.

The possible outcomes are:  (3, 6), (4, 5),  (5, 4)

P(\text{two numbers whose sum})=\frac{3}{36}=\frac{1}{12}

10) Probability of getting two numbers whose sum is 4.

The possible outcomes are:  (1, 3),(2, 2),(3, 1),

P(\text{two numbers whose sum})=\frac{3}{36}=\frac{1}{12}

11.)Find the probability of getting two numbers whose sum is less than 7.

The possible outcomes are: (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (2, 1), (2, 2), (2, 3), (2, 4),  (3, 1), (3, 2), (3, 3),  (4, 1), (4, 2),  (5, 1)

P(\text{two numbers whose sum is less than 7})=\frac{15}{36}=\frac{5}{12}

12.Probability of getting two numbers whose sum is greater than 8

The possible outcomes are:(4, 5), (4, 6),  (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6)

P(\text{two numbers whose sum is greater than 8})=\frac{9}{36}=\frac{1}{4}

(13)Probability of getting two numbers that are the same (doubles).

The possible outcomes are:(1, 1)(2, 2), (3, 3), (4, 4),  (5, 5), (6, 6)

P(\text{two numbers that are the same})=\frac{6}{36}=\frac{1}{6}

14.Probability of getting a sum of 7 given that one of the numbers is odd.

The possible outcomes are: (2, 5),  (3, 4), (4, 3), (5, 2),  (6, 1)

P(\text{getting a sum of 7 given that one of the numbers is odd.})=\frac{5}{36}

(15)Probability of getting a sum of eight given that both numbers are even numbers.

The possible outcomes are: (2, 6), (4, 4), (6, 2)

P(\text{getting a sum of eight given that both numbers are even numbers.})=\frac{3}{36}\\=\frac{1}{12}

16.Probability of getting two numbers with a sum of 14.

P(\text{getting two numbers with a sum of 14.})=\frac{0}{36}=0

4 0
4 years ago
Y/3-a=b solve for y
madam [21]
Y/3-a=b

First multiply 3 on both sides
y/3-a=b
*3        *3
---------------
y-a=3b

Now add the a on both sides
y-a=3b
 +a    +a
----------------
y=3b+a

Your answer is 
Y=3b+a
7 0
3 years ago
One machine can complete a job in 10 minutes. If the same job is done by this machine and an older machine working together, the
nalin [4]

Answer:

15 minutes

Step-by-step explanation:

The speed of the first machine is 1/10 job/minute.

The speed of the older machine is x.

Their combined speed is:

x + 1/10 = 1/6

Solving for x:

x = 1/6 − 1/10

x = 5/30 − 3/30

x = 2/30

x = 1/15

The speed of the older machine is 1/15 job/minute, so it takes 15 minutes for the older machine to do the job alone.

7 0
3 years ago
Pls help me answer this​
Mnenie [13.5K]

Answer:

C

Step-by-step explanation:

Bc everything is positioned right

I hope this helps

4 0
3 years ago
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