1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pentagon [3]
2 years ago
11

D.sqrt(2+x^/2) Solve this question please

Mathematics
1 answer:
lidiya [134]2 years ago
7 0

Answer:

Option a.

Step-by-step explanation:

By looking at the options, we can assume that the function y(x) is something like:

y = \sqrt{4 + a*x^2}

y' = (1/2)*\frac{1}{\sqrt{4 + a*x^2} }*(2*a*x) = \frac{a*x}{\sqrt{4 + a*x^2} }

such that, y(0) = √4 = 2, as expected.

Now, we want to have:

y' = \frac{x*y}{2 + x^2}

replacing y' and y we get:

\frac{a*x}{\sqrt{4 + a*x^2} } = \frac{x*\sqrt{4 + a*x^2} }{2 + x^2}

Now we can try to solve this for "a".

\frac{a*x}{\sqrt{4 + a*x^2} } = \frac{x*\sqrt{4 + a*x^2} }{2 + x^2}

If we multiply both sides by y(x), we get:

\frac{a*x}{\sqrt{4 + a*x^2} }*\sqrt{4 + a*x^2} = \frac{x*\sqrt{4 + a*x^2} }{2 + x^2}*\sqrt{4 + a*x^2}

a*x = \frac{x*(4 + a*x^2)}{2 + x^2}

We can remove the x factor in both numerators if we divide both sides by x, so we get:

a = \frac{4 + a*x^2}{2 + x^2}

Now we just need to isolate "a"

a*(2 + x^2) = 4 + a*x^2

2*a + a*x^2 = 4 + a*x^2

Now we can subtract a*x^2 in both sides to get:

2*a = 4\\a = 4/2 = 2

Then the solution is:

y = \sqrt{4 + 2*x^2}

The correct option is option a.

You might be interested in
Please help with this
eimsori [14]

Answer:

this is hard

Step-by-step explanation:

7 0
2 years ago
Solve the equation. Then check your solution
kondaur [170]

Answer:

  • Option <u>B </u>is correct i.e. <u>2</u><u>1</u>

Step-by-step explanation:

In the question we're provided with an equation that is :

  • v/7 = 3

And we are asked to find the solution for the equation .

<u>Solution</u><u> </u><u>:</u><u> </u><u>-</u>

<u>\longrightarrow \:  \frac{v}{7}  = 3</u>

Multiplying by 7 on both sides :

\longrightarrow \: \frac{v}{ \cancel{7} }\times  \cancel{7}  = 3 \times 7

On further calculations , we get :

\longrightarrow \:  \blue{\boxed{v = 21}}

  • <u>Therefore</u><u> </u><u>,</u><u> </u><u>solution</u><u> </u><u>for</u><u> equation</u><u> </u><u>is </u><u>2</u><u>1</u><u> </u><u>.</u><u>That </u><u>means</u><u> </u><u>option </u><u>B </u><u>is </u><u>the </u><u>correct</u><u> answer</u><u>.</u>

<u>Verifying</u><u> </u><u>:</u>

We are verifying our answer by substituting value of v in the equation given in question :

\longrightarrow \: \frac{v}{7}  = 3

Putting value of v :

\longrightarrow \:  \cancel{\frac{21}{7}}  = 3

By dividing 21 with 7 , we get :

\longrightarrow \:3 = 3

\longrightarrow \: L.H.S=R.H.S

\longrightarrow \: Hence , \: Verified.

  • <u>Therefore</u><u> </u><u>,</u><u> </u><u>our </u><u>answer</u><u> is</u><u> valid</u><u> </u><u>.</u>

<h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
3 0
2 years ago
Read 2 more answers
A runner can travel 100 meters in 20 seconds. At that rate, how far does the runner go in 1 minute?
dimaraw [331]

Answer:

he can run 5 meters in 1 min

Step-by-step explanation:

S = d/t

S=100m/20s

S=5m/s

8 0
3 years ago
Simply the expression by combining like terms 20c+8d+10c-5d​
valentinak56 [21]

First, combine 20c and 10c because they are like terms then combine 8d and -5d.  

It would look like this:

20c+8d+10c-5d

30c+3d

Hope that helps

6 0
2 years ago
1.What are the zeros of the polynomial function?
Lorico [155]
Let's to the first example:

f(x) = x^2 + 9x + 20

Ussing the formula of basckara

a = 1
b = 9
c = 20

Delta = b^2 - 4ac

Delta = 9^2 - 4.(1).(20)

Delta = 81 - 80

Delta = 1

x = [ -b +/- √(Delta) ]/2a

Replacing the data:

x = [ -9 +/- √1 ]/2

x' = (-9 -1)/2 <=> - 5

Or

x" = (-9+1)/2 <=> - 4
_______________

Already the second example:

f(x) = x^2 -4x -60

Ussing the formula of basckara again

a = 1
b = -4
c = -60

Delta = b^2 -4ac

Delta = (-4)^2 -4.(1).(-60)

Delta = 16 + 240

Delta = 256

Then, following:

x = [ -b +/- √(Delta)]/2a

Replacing the information

x = [ -(-4) +/- √256 ]/2

x = [ 4 +/- 16]/2

x' = (4-16)/2 <=> -6

Or

x" = (4+16)/2 <=> 10
______________

Now we are going to the 3 example

x^2 + 24 = 14x

Isolating 14x , but changing the sinal positive to negative

x^2 - 14x + 24 = 0

Now we can to apply the formula of basckara

a = 1
b = -14
c = 24

Delta = b^2 -4ac

Delta = (-14)^2 -4.(1).(24)

Delta = 196 - 96

Delta = 100

Then we stayed with:

x = [ -b +/- √Delta ]/2a

x = [ -(-14) +/- √100 ]/2

We wiil have two possibilities

x' = ( 14 -10)/2 <=> 2

Or

x" = (14 +10)/2 <=> 12
________________


To the last example will be the same thing.

f(x) = x^2 - x -72

a = 1
b = -1
c = -72

Delta = b^2 -4ac

Delta = (-1)^2 -4(1).(-72)

Delta = 1 + 288

Delta = 289

Then we are going to stay:

x = [ -b +/- √Delta]/2a

x = [ -(-1) +/- √289]/2

x = ( 1 +/- 17)/2

We will have two roots

That's :

x = (1 - 17)/2 <=> -8

Or

x = (1+17)/2 <=> 9


Well, this would be your answers.


7 0
3 years ago
Other questions:
  • (3x2 – 2) + (2x2 - 6x + 3)<br> Simplified?
    11·2 answers
  • I need it in standard form &amp; to be simplified
    7·1 answer
  • Find the measurement indicated in each parallelogram <br> (Same thing as the other one I posted)
    12·2 answers
  • 25 is 32% of what number? Round to the nearest tenth if necessary.
    15·2 answers
  • Geometry please help thank you
    10·1 answer
  • How do I solve 1/8x=5
    6·2 answers
  • A hiker has 2 pairs of hiking shoes, 3 shirts, and 5 pairs of shorts to choose from. How does the number of combinations of shoe
    13·1 answer
  • What is the value of the expression?
    15·1 answer
  • Two artists are mixing up green paint for a mural. The first artist, Shane, mixes 3 parts blue and 2 parts yellow to make a shad
    10·1 answer
  • Plot points between and beyond each X intercept and vertical asymptote find the value of the function at the given value of XFra
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!